Standing-Wave Current vs Traveling-Wave Current
Roger wrote:
Keith Dysart wrote:
clip ....
In the setup above used for "standing waves"
it can be seen that there is zero power in
the line every 90 degrees back from the open
end. At a zero power point, no energy is
being transferred. Therefore, the forward
and reverse waves can not be transferring
energy across these points. Conclusion:
forward and reverse waves do not always
transport energy.
....Keith
Hi Keith,
You are basing this conclusion on the observation that Power = V*I, and
because we can not detect V or I at some points in the standing wave,
then V*I is zero at these points. Correct math, but wrong conclusion.
What you are forgetting is that power is also found from Power = V^2/Zo
and Power = I^2*Zo. More accurately, on the standing wave line,
Power = (V^2 + I^2)/Zo. This is why a SWR power meter detects both
current and voltage from the standing wave.
This will also be true on the quarter wave stub, which is really 1/2
wave length long electrically, when you consider the time required for
the wave to go from initiation to end and back to beginning point. Power
is stored on the stub during the 1/2 cycle energized, and then that
stored power acts to present either a high or low impedance to the next
1/2 cycle, depending upon whether the stub is shorted or open.
I think you did a very good job in building your theory. It was only at
the end (where I think we need to consider additional ways of measuring
power) that we disagree.
73, Roger, W7WKB
Haste makes waste, and errors as well. The standing wave power
equation is incorrect. It should read "Power = V^2 / Zo + I^2 * Zo"
Sorry for any inconvenience, and for the several postings it will
probably stimulate.
73, Roger, W7WKB
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