Not if the voltage and current are always 90 degrees out of
phase which is a fact of physics for pure standing waves. There
is no power, instantaneous or otherwise, in pure standing waves.
The cosine of 90 degrees is *always* zero.
--
************************************************** *******************************8

Cecil, your technical and mathematical skills vastly exceed mine... My
poor little monkey brain has to work in the concrete, not the
abstract...
I sort of understand the concept of the standing wave being the
instantaneous vector product of two colliding EM wave fronts...
I accept the fact that MATHEMATICALLY; P = V*I* cos (theta).... And
being that theta is DEFINED as 90 degrees the cos = 0, so the
instantaneous power is zero...
But here is where the math breaks down...
On my herd of 100KW RF generators... Every time the load failed for
even a split second, those fire breathing dragons would blow a hole
through the quarter inch thick slabs of copper that made up the line,
instantaneously...
To prove that mathematically there is no power contained in a standing
wave collides with my, farm boy, real world, physics experiments...
The voltage peak on that line when that standing wave forms is real,
it has mucho power (esp when driven by the dragon breath of a 100KW
triode with 15KV on the plate), and it blows the hole in the line at
the same distance from the load every time (proof of standing wave
theory)...

This is why i have a problem accepting that a standing wave contains
no power - regardless of the prominence of the men who wrote the
textbooks..

cheers ... denny