Standing-Wave Current vs Traveling-Wave Current
On Dec 29, 9:59*am, Cecil Moore wrote:
Keith Dysart wrote:
Still sidetracking away from your demons rather
than confronting them?!
No, you are the one who believes in the supernatural,
not I. I have confronted those supernatural demons
and decided they don't even exist in reality.
Well something causes you to latch up and bail with
"its not real world", though there was no protest
when the initial experiment is specified using
ideal elements.
But when the line is cut, it is clear that no
energy is moving between the separate sections.
Just as it is clear that before the cut, energy
was moving between the separate sections. It
requires belief in a supernatural to assert that
is not a change.
But you previously agreed that P(t) = 0 for all t,
and therefore no energy was moving between the sections.
Recall that P(t) = V(t) * I(t) and that at the
point on the line in question, I(t) is zero for all
t, therefore P(t) is zero for all t. So no energy
flow between the sections.
When the lines are joined, the voltage, current and
power distributions on the line remain the same.
Therefore, no energy is being transferred between
the now joined sections.
QED
Change the QED to BS and you will have it right.
This is the kind of comment that suggests stress,
rather than rational examination.
When the lines are joined, there is no longer a
physical impedance discontinuity so reflections
are impossible and energy starts flowing again
in both directions.
But as previously discussed, no energy flows. The
the voltage, current and power distributions are
the same, whether the line is cut or joined.
Believing that reflections can occur where there
exists no physical impedance discontinuity is a
religion, not a science.
Red herring. Straw man. I do not recall anyone
making the claim that reflections exist with no
physical impedance discontinuity. (Although you
did raise the possibility in another post).
At that point, I draw
the line - but you are free to have the religion
of your choice. Just please don't try to force
your religion on this technical newsgroup.
With or without reflections, no energy crosses
the points on the line with zero current.
Make that no *NET* energy and you will be so
technically correct that I will agree with you.
Sometimes when writers write NET, they mean time
averaged, but that is not your intent here, is it?
You do mean that P(t) is zero for all t at the
points on the open circuited line where the voltage
or current is always zero. Right?
...Keith
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