On Dec 31, 1:27*am, Cecil Moore wrote:
Keith Dysart wrote:
And a Thevenin source can be transformed into an
equivalent Norton source. Example...

A 100 V ideal voltage source in series with 50 ohms
has exactly the same output characteristics as a
2 amp ideal current source in parallel with a 50 ohm
resistor. Test using any load impedance: open, short,
any resistance value.

Indeed, take a look at the internal power dissipation
for an open and short and tell us again why those
sources are identical.

Are you saying that there output characteristics are
different because of differing internal power dissipations?

And are you not the lad who mentioned that one should
never examine the internal power dissipation of a Norton
or Thevenin equivalent circuit because, in general, it
bears no relation to the dissipation in the real
circuit? Or have you changed your view?

...Keith