Corrections:

Roy Lewallen wrote:
. . .
From the voltage analysis and the SPICE plot, the initial voltage at
the input of the line is sin(wt). So the voltage across the input
resistor is 3 * sin(wt) (+ toward the source), and the current flowing
into the line is (3 * sin(wt)) / 150 = 20 * sin(wt) mA. The average
power being delivered to the line is Vin(rms) * Iin(rms) (since the
voltage and current are in phase) = (0.7071 v. * 14.14 mA) = 10 mW.
Since the line initially presents an impedance of Z0, this should also
be Vin(rms)^2 / Z0 or Iin(rms)^2 / Z0. . . .

The last sentence should read:

Since the line initially presents an impedance of Z0, this should also
be Vin(rms)^2 / Z0 or Iin(rms)^2 * Z0. . . .

The calculations which follow were done using the correct formula, so
the mistake had no effect on the following steps or the conclusions.

I also carelessly and incorrectly used j as an abbreviation for joules
throughout the posting. The correct abbreviation is J. (And yes, the
name of the unit is correctly joule, not capitalized, as is the case for
most if not all SI units named after people.) This mistake is made
potentially worse because of the possible confusion with the imaginary
operator j (as used by electrical engineers). I apologize for any
confusion the mistake might have caused.

Thanks very much to the careful and thoughtful reader who brought these
errors to my attention.

Roy Lewallen, W7EL