OK Cecil. I understand that none of your discussion applies to instantaneous values, only average values.
I am examining Keith's spread sheet carefully. I found that Open Calc will open the spreadsheet so I can read Keith's cell directions. (Thanks for making the spread sheet available Keith.) I want to make sure that I fully understand what is happening here, to the best of my ability and time available.
On Fri, 07 Mar 2008 12:13:45 -0600
Cecil Moore wrote:
Roger Sparks wrote:
On Fri, 07 Mar 2008 15:15:08 GMT
Cecil Moore wrote:
My formula applies *only to average power*.
I find myself surprised at your insistance that the instantaneous
case must be seperated from the average case in our example of waves
on a transmission line.
You have misunderstood what I am objecting to - which is:
Please don't say or imply that I have said or implied
anything about instantaneous values. I have NOT done so!
The formulas and concepts being used in the discussion
of instantaneous values are NOT mine! My objection is
to the false statements being made about what I have
posted.
Please go ahead and have your instantaneous discussion with
Keith but please don't say or imply that anything associated
with that discussion is about anything I have posted. Saying
or implying such a thing is simply false.
It is informative to look at each problem from many angles.
I agree - just stop saying that it is based on my assertions.
You or Keith may be right or wrong but either way, it is not
associated with anything I have posted. Please leave my name
out of any discussion concerning instantaneous values.
Did I misunderstand your premise, and you were really trying to say that
the inclusion of a 50 ohm source resistor would prevent the source from
ever 'seeing' anything but a 100 ohm load? I don't think that was your
intent.
Please add a dimension to your thinking. No matter what the
value of the load resistor, the source delivers 100 watts.
There are an infinite number of loads that the source could
"see" besides 100+j0 ohms that will make that condition true.
When the load is 0 ohms, the source "sees" 50+j50 ohms.
When the load is 12.5 ohms, the source "sees" 73.5+j44.1 ohms.
When the load is 25 ohms, the source "sees" 90+j30 ohms.
Only when the load is 50 ohms, does the source "see" 100+j0 ohms.
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73, Cecil http://www.w5dxp.com
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73, Roger, W7WKB