On Mon, 17 Mar 2008 03:00:10 -0700 (PDT)
Keith Dysart wrote:
On Mar 17, 1:06*am, Cecil Moore wrote:
Keith Dysart wrote:
Pr.g(t) = -50 + 50 *cos(2wt)
* * * * = -50 -50
* * * * = -100
which would appear to be the 100 watts needed to
heat the source resistor.
Thanks for a comprehensive analysis Keith. It was helpful to me to see how you step by step analyzed the circuit.
--
73, Roger, W7WKB