Roger Sparks wrote:
Keith Dysart wrote:
Pr.g(t) = -50 + 50 cos(2wt)
= -50 -50
= -100
which would appear to be the 100 watts needed to
heat the source resistor.

Thanks for a comprehensive analysis Keith. It was helpful to me to see how you step by step analyzed the circuit.

Note that his analysis proves that destructive interference
energy is indeed stored in the reactance of the network and
dissipated later in the cycle as constructive interference
in the source resistor at a time when the instantaneous
source power equals zero.
--
73, Cecil http://www.w5dxp.com