Keith Dysart wrote:
And using your definition, that there is no interference
when (V1**2 + V2**2) = (V1+V2)**2, it can be seen that
for the circuit at hand, your Fig 1-1, there is zero
interference in the terms you wish to add, four times
in each cycle.

Correction for omitted word above: And using my
definition, that there is no *average* interference
when (V1**2 + V2**2) = (V1+V2)**2,"
Those are average (RMS) values of voltage.

The test for zero *instantaneous* interference is:
[V1(t)^2 + V2(t)^2] NOT= [V1(t)^2+V2(t)^2]
Those are instantaneous values of voltage.

Please correct your confusion about what I have said.
It is also clear that you don't understand when
interference exists and when it doesn't.

The instantaneous destructive interference equals
the instantaneous constructive interference 90
degrees later. That's why the interference averages
out to zero.

I believe, although I have not taken the time to
prove it, that the instantaneous interference is
zero only at the zero-crossings of the source
voltage and reflected voltage.

Again, the existence and magnitude of the
instantaneous interference is irrelevant to
the assertions in my Part 1 article. It is
obvious that the interference averages out
to zero over each cycle for the example
presented.
--
73, Cecil http://www.w5dxp.com