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Old April 22nd 08, 06:12 PM posted to rec.radio.amateur.antenna
Cecil Moore[_2_] Cecil Moore[_2_] is offline
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First recorded activity by RadioBanter: Mar 2007
Posts: 3,521
Default The Rest of the Story

Cecil Moore wrote:
Keith Dysart wrote:
What I have said is that an ideal voltage source removes energy
from a circuit ...


Sorry, you specifically said that an ideal voltage source
"absorbs" energy, i.e. irreversibly converts energy to
another form, the most common form of which is heat.


In case you have forgotten :-), here is what you posted
over the past few days:

When it is sinking current, it is *absorbing* energy.

You will find that for some of the time
energy is being *absorbed* by the source.

But we do know that when the sign of Ps(t) is
negative, the source is *absorbing* energy from
the system,

When current flows into a voltage source, the
voltage source is *absorbing* energy.

And how do you know the ideal source does not dispose
of the energy it receives by getting warm?


This certainly implies that you consider the dissipation
of "absorbed" energy to be a distinct probability.

The source provides or *absorbs* energy.

When 1.5 amps is flowing into the positive terminal,
the ideal voltage source is *absorbing* 15 joules per
second from the circuit.

The ideal voltage source on the right is *absorbing*
5 joules/second from the circuit.

An ideal source provides or *absorbs* energy to
satisfy its basic function which is to hold the
voltage across its terminals at the desired value.

When it is providing energy we do not know where
this energy comes from and when it is *absorbing*
energy we do not know where this energy goes.

But was this because you have learned that you were
in error and now better understand the behaviour of
sources when they are *absorbing* energy?

The ideal voltage source on the right, after the
circuits settle, will be absorbing 50 joules/s
in both cases.

Where does the energy being *absorbed* by these ideal
voltage sources go?

The element *absorbing* energy is an ideal voltage
source, not a resistor.

Despite your protests to the contrary, ideal voltage
sources can, and do, *absorb* energy.


You know, Keith, if you were just ethical enough to
answer my questions, I wouldn't have to treat you
this way.
--
73, Cecil http://www.w5dxp.com