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Efficiency and maximum power transfer
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June 14th 08, 06:43 AM posted to rec.radio.amateur.antenna
Alan Peake[_2_]
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First recorded activity by RadioBanter: Feb 2008
Posts: 28
Efficiency and maximum power transfer
wrote:
On Jun 6, 9:15 pm, Walter Maxwell wrote:
Since E/I is simply a ratio, R is also a ratio. And we know that a
ratio cannot dissipate power, or turn electrical energy into heat,
thus the output resistance R is non-dissipative. I have made many
measurements that prove this.
Hi Walt,
R is by definition a physical "property of conductors which depends
on dimensions, material, and temperature". So if we multiply both
sides of our "ratio" equation by I^2 to convert to power we get V*I =
I^2*R. Given that V, I, and R are all non-zero, why would you ask
us to believe that I^2*R and V*I could be zero? It's true that V^2/R
is a ratio. And I guess it's probably also true that the equation
itself doesn't dissipate power. But what would you have us believe
that that is supposed to prove?
73, Jim AC6XG
I always believed that a ratio was a comparative measure between like
units - e.g. forward voltage to reverse voltage, output power to input
power etc. Voltage to current is not a ratio. V/I has dimensions of
resistance - ratios are dimensionless.
Alan
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