Efficiency and maximum power transfer
On Jun 13, 10:43*pm, Alan Peake wrote:
wrote:
* On Jun 6, 9:15 pm, Walter Maxwell wrote:
*
* Since E/I is simply a ratio, R is also a ratio. And we know that a
* ratio cannot dissipate power, or turn electrical energy into heat,
* thus the output resistance R is non-dissipative. I have made many
* measurements that prove this.
*
*
* Hi Walt,
*
* R is by definition a physical "property of conductors which depends
* on dimensions, material, and temperature". *So if we multiply both
* sides of our "ratio" equation by I^2 to convert to power we get V*I =
* *I^2*R. *Given that V, I, and R are all non-zero, *why would you ask
* us to believe that I^2*R and V*I could be zero? *It's true that V^2/R
* is a ratio. *And I guess it's probably also true that the equation
* itself doesn't dissipate power. *But what would you have us believe
* that that is supposed to prove?
*
* 73, Jim AC6XG
I always believed that a ratio was a comparative measure between like
units - e.g. forward voltage to reverse voltage, output power to input
power etc. Voltage to current is not a ratio. V/I has dimensions of
resistance - ratios are dimensionless.
Alan
Good point. You may be right.
73 de jk
|