K7ITM wrote:
On Aug 22, 3:23 pm, Roy Lewallen wrote:
Is the sine wave applied and the load, if any, connected such that the
currents in the two wires are equal and opposite? If so, the problem
becomes exactly the same as a single wire suspended above and parallel
to an infinite perfect ground plane. In the plane exactly midway between
the wires -- the position represented by the perfect ground plane in the
simplified model -- the field is zero, since the fields from the two
wires are equal and opposite in that plane. If the currents aren't equal
and opposite, the problem becomes considerably more complex.
. . .
Roy Lewallen, W7EL

Hmmm...I don't think that's quite right, Roy. I expect the E field
between the wires, in the plane of the wires, to be parallel to the
plane, perpendicular to the wires, if there is a potential between the
wires and they are straight and parallel. For a wire above ground,
the E field must be perpendicular to the ground at the ground (assumed
perfect), but it's not zero in general.

Cheers,
Tom

Tom is completely right -- as always. The problem is, as I said, the
same as a single wire suspended above a perfect conducting plane. The E
field is perpendicular to the conducting plane (that is, in the plane
containing the wires as Tom said) and not zero as I incorrectly said.
Thanks for the correction, Tom, and my apology to all for the error.

Roy Lewallen, W7EL