"Jerry" wrote in message
...

- snip -

I am having a block in my learning. As I understand it, this would
actually happen if it could be performed.

Yes


A spinning dipole would require more power to spin it if it had DC on it
than if it had no DC on it.

Yes - as I said, the means of spinning the dipole would be the counterpart
to the 'transmitter'

And, actually, it would require no power to keep the dipole spinning since
there would be that theoritical vacuum around it.

If you say so - you're specifying a hypothetical zero-friction system which
is but one of several possible scenarios.

But, once you apply the DC, power would be required to keep it spinning.
That amount of added power would be determined by the amount of DC
applied. Do you confirm that this is true?

Certainly work would need to be done to spin the dipole and create the
outgoing wave by virtue of its rotation. I suppose it follows that the
strength of the outgoing wave would be proportional to the applied voltage
but I'm not certain that a greater voltage would require more mechanical
work to spin the dipole - you may be right but I'm not certain I can confirm
this from what I think I know!

My question relates to my ignorance about what there is in the "vacuum"
to cause "drag".

Jerry KD6JDJ

I'm afraid I had taken very little account of causes of mechanical drag. As
noted before, this was a thought experiment - the sort of thing that can
reach a useful conclusion (i.e. 'not likely' in this case!) without
requiring detailed examination of what may be 'second-order' influences.

Chris