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Old May 12th 09, 09:29 PM posted to rec.radio.amateur.antenna
Szczepan Białek Szczepan Białek is offline
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First recorded activity by RadioBanter: May 2009
Posts: 197
Default wave polarisation


"Richard Clark" wrote
...
On Tue, 12 May 2009 18:00:09 +0200, Szczepan Bia?ek
wrote:

The topics is polarisation. This word has the two meaning. The both have
wrong explanations in texbooks. The one I have verified with the comb.
The second "wave polarisation" is explained with transverse waves. No
transverse waves. If receiver (resonator) must be parallel to emmiter you
can explain it in many ways. But to verify it the comb is not enough. So I
need help.


That is fair. Let's start with some serious misunderstandings with a
few questions to test them.

First, let us return to that link you offered with the Hertzian Loop
with its spark gap. Let us say that this loop is 1 meter of wire
(about the actual size anyway). Let us say there is a current
detector at each end of this loop. Let us say we have closed a switch
that applies voltage to the loop, and the first meter has indicated
current flow. This is our time reference point. Now the questions:

1. For the electron that went through the first current detector, how
long does it take for that SAME electron to get to the second
detector?

2. How long does it take for the second detector to indicate there is
current flow?

Hint: the answer for 1. is very, very different for the answer for 2.

Now, let us say that before that SAME electron gets to the second
current detector, that path is broken open (maybe 1 pico second before
the SAME electron arrival). The SAME electron sees an open circuit.
What is the amount of energy required for the electron to break out of
the metal conductor, and into the air?


You went to details. Early you wrote: "An antenna radiates in ALL directions
from EVERYPOINT of
the antenna. "
Textbooks say that EM transversial waves are emitted by current (the sparks
in Hertz apparatus - not from the ends).
I say that from the ends (as electric waves similar to acoustics).
The directional pattern must be different.
The directional patterns of loudspeakers and Herts dipoles are very
similar.
So I try to find evidences.
Now I do not know if you prefer EM or electric waves.
S*