On Tue, 12 May 2009 21:29:31 +0200, Szczepan Bia?ek
wrote:

You went to details. Early you wrote: "An antenna radiates in ALL directions
from EVERYPOINT of
the antenna. "

They do.

Textbooks say that EM transversial waves are emitted by current (the sparks
in Hertz apparatus - not from the ends).

That is not the same thing as radiation. Repeating poor quotations
does not make it better.

I say that from the ends (as electric waves similar to acoustics).

Compressional waves or longitudinal waves? In solid or air or in
liquid? The answers to these questions lead to very, very different
behavior. As I say, these simplicities you use are nonsense.

The directional pattern must be different.

The directional pattern is a combination of EVERYPOINT radiating in
ALL directions. The differences in their position contribute to an
unique pattern. This is the whole basis of the "method of moments"
application of modeling radiation emitters.

The directional patterns of loudspeakers and Herts dipoles are very
similar.

The are more differences than similarities.

So I try to find evidences.
Now I do not know if you prefer EM or electric waves.

That shouldn't keep you from answering the simple physics of:
Let's start with some serious misunderstandings with a
few questions to test them.

First, let us return to that link you offered with the Hertzian Loop
with its spark gap. Let us say that this loop is 1 meter of wire
(about the actual size anyway). Let us say there is a current
detector at each end of this loop. Let us say we have closed a switch
that applies voltage to the loop, and the first meter has indicated
current flow. This is our time reference point. Now the questions:

1. For the electron that went through the first current detector, how
long does it take for that SAME electron to get to the second
detector?

2. How long does it take for the second detector to indicate there is
current flow?

Hint: the answer for 1. is very, very different for the answer for 2.

Now, let us say that before that SAME electron gets to the second
current detector, that path is broken open (maybe 1 pico second before
the SAME electron arrival). The SAME electron sees an open circuit.
What is the amount of energy required for the electron to break out of
the metal conductor, and into the air?

73's
Richard Clark, KB7QHC