"Szczepan Bialek" wrote in message
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"Dave" wrote
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"Szczepan Bialek" wrote in message
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In the Hertz apparatus the charges (electrons) have at the centre the
max velocity and the acceleration equal zero.
At ends the situation is opposite. So your answer should be: "the ends
radiate of course".

of course you are wrong. there is a smooth transition between the center
and the ends, that whole length radiates. you can't just look at the
boundry conditions, you have to consider the whole length.

Yes. But the radiation is not uniform. What radiate stronger: the centre
or the ends?

both. when the current is high in the center it is creating a stronger
magnetic field, and when that current reaches the end it creates the highest
voltage so makes more electric field... both are part of the
electro-magnetic wave.



It is very funny that engineers use electrons and do not know that in
the "Maxwell's equations" no electrons, There is incompressible massless
fluid.
You here do not use the "Maxwell's equations". The teachers use them to
teach math.
Engineers use the empirical equations following the rule "accelerating
charges create radiation".

Gauss's law is about charged particles, the one art so much likes to
distort.. and don't forget that the 'i' term is also about charged
particles moving... if they can move they are not imcompressible, and
since the force on them can be measured and accelerations are not
infinite they are not massless.

We all know now that the electrons are "not imcompressible, and since
the force on them can be measured and accelerations are not infinite they
are not massless."
But do you know what the electricity was like in the Maxwell theory from
1865?

sure, its the same as today. since his equations still work the electricity
hasn't changed.