On Sep 3, 10:26*am, Art Unwin wrote:

Yes, that is correct, but the power used on a 1/2 wave dipole is
half that of a full wave.

A full wave what? Are you calling a folded 1/2-wave dipole a full-
wave antenna?

For equal, matched power applied either to a 1/2-wave dipole or to a
folded 1/2-wave dipole, and although their feedpoint currents will be
different, both configurations will generate the same values of field
intensity.

Also how do you explain this, given that the 1/2-wave dipole by your
definition does not have "equilibrium?"

RF