On Sep 21, 7:33*pm, "christofire" wrote:
"Art Unwin" wrote in message

...
On Sep 21, 4:19 pm, "christofire" wrote:

"Art Unwin" wrote in message

- - snip - -

Chris you are being stupid as well as acting as a fool.
Acceleration of the particle only occurs while within the
electrostatic field. When it exits it has the speed of light because
it has emmerged from the intersecting two fields.and thus from *the
accellerating forces. I remind you of Newtons law of ut + 1/2 ft sqd
The first expression is for the speed attained on entering the
accelerating field and the other half is for the length of the
accelerating electrostatic field. On leaving the two fields it looses
the applied accelerating force where it has arrived at a particular
speed.Maybe you should look up the workings of a CRT using Newtons
laws instead of shooting from the hip.
It was at a different time that the speed of light was measured where
it was found to equal the sppeed emerging from two intersecting fields.

* Actually, I'm well aware of the principle involved in accelerating
electrons in an electron gun as used in CRTs, klystrons, TWTs, and so on, by
subjecting an electron cloud to a potential difference using an anode with a
hole in it (!), but that's different from what happens in an antenna.

The acceleration of charge in an antenna results almost entirely from the
applied potential difference at its terminals. *The radiated fields result
from the alternating current effectively passing through the radiation
resistance, and all the other, reactive, fields have no direct effect on the
radiation resistance, or the component of the current that passes through it
in phase with the voltage that is developed across it, which together, of
course, represent the radiated power. *The reactive fields affect the
terminal impedance and a large imaginary part can upset the device trying to
send power into the antenna, but that is more of a system issue. *The
alternating current that passes through the radiation resistance is composed
of charge that moves in time with each RF cycle, accelerating and
decelerating accordingly. *The electrostatic field developed between the
ends of a half-wave dipole reaches its maximum value a quarter of a cycle
later than the voltage at the drive point so any effect it has on the charge
in the antenna elements during each cycle must be reactive, and it doesn't
affect the radiation resistance or the radiated wave.

But all this can be looked up from any one of the respected books on
antennas. *Krauss, and others, gives expressions for the different field
components and the theory all hangs together quite readily using Maxwell's
equations without modification.

I don't care if you think me stupid, and I'll continue to try to avoid name
calling of individuals, although I may criticise what they write especially
if it appears ignorant of proper science yet attempts to re-write
established theory, and therefore appears arrogant.

Chris

No it does not appear in Kraus book. He never followed Maxwells laws
with respect to equilibrium. To do that you must think in terms of
wavelength. After all with respect to science all revolve around
boundary laws of the Universe and you blindly ignore that fact.
Now back to radiation which applies spin to a p. Nowarticle where as
with a crt no spin is applied as it is heat that separates the resting
particle Now earlier you refered to a electrostatic field that
according to what you stated did not have a border and surely you know
that just can't be unless it is in equilibrium which requires a closed
circuit.
For this to come to fruition you go back to the boundary laws where
the arbitrary border is one that is closed i.e. in equilibrium. Now
cast your mind back to the Gauss extension where radiators and
particles lie in a closed static field. Now you should see that
equilibrium must reign for a closed static field. Now you blithely
mentioned an electrostatic field with nary a mention as to how it is
formed and how it fits into the whole picture.
Why? Because the books do not provide an unbroken trail that fully
describes radiation
( books admit that) as I have done where everything dove tails into
the existing laws of the Universe. And then I gave you a bonus with
respect to the weak field that Einstein searched for in vain. Einstein
looked at the package presented by the Big Bag but omitted to keep
that which it was wrapped into. That was the arbitrary boundary around
which were forces or vectors that were equal and opposite when a
smallest of smallest of particles edged out towards the border. Yes it
was of a weak force but for all of that it broke the equilibrium
boundary as the forces at that point was not now equal. The breakage
was one where the opposing forces were offset to each other thus
providing a torque force that provided spin. Now we come to our own
Earth encased in a arbitrary border and outside the border we have the
same conditions of equilibrium that must equal the forces of the Big
Bang which means the outside has two vectors, gravity vector which is
straight and a vector denoting spin i.e. rotation of the Earth. On the
other side of the border you again have two vectors a straight vector
and that curly one you don't like me to call eddy current.
Yup. Everything falls together nicely thank you, when you study
radiation from first principles instead of binding yourself to books
that readily admit to not understanding the radiation process. Now
this is not being arrogant when one has applied all principles but I
do think it is arrogant of you and others to asasinate the character
of "S" purely because of his english and spelling and not to help one
that wants to learn.
Just think about it all. I have shown how a particle moves in space in
a straight line trajectory such that the particle maintains a straight
line without the parabolic force of gravity driving it down to the
Earth. Go back to your books and show just how the electrostatic field
came about and what was the borders that it was contained in
Art
via applied spin and where gravity