On Jun 4, 8:23*pm, joe wrote:
Keith Dysart wrote:
On Jun 4, 1:26 pm, K1TTT wrote:
On Jun 4, 2:12 pm, Cecil Moore wrote:
Thanks David, that's good news. It apparently means that the arguments
based on energy not crossing a current node boundary in a standing
wave are invalid - since that singular condition violates the boundary
conditions for Maxwell's equations. So does the "standing wave energy
standing still" argument. Not only does the photonic nature of EM
waves require them to travel at the speed of light in the medium, but
so does Maxwell's equations.
definately. *another simple condition shows this can't be correct
since current nodes correspond with voltage peaks in the standing wave
pattern, so while energy in the magnetic field is a minimum the energy
in the electric field is a maximum.

And yet....

It is generally accepted that power = volts times current (P=VI) and
that
power is energy flowing, so if the voltage or current is always 0,
there
must be no energy flowing.

Consider two equal valued resistors connected in series. Connect one end
of the pair to +12 volts, connect the other end of the pair to -12
volts. *The voltage at the center is 0. There is certainly current
flowing. There clearly is power dissipated in the circuit.

An excellent example. Let's draw it.

A
+----\/\/\------+-----/\/\/\----+
| |
--- -
- ---
| B |
+---------------+---------------+

Between A and B the voltage is zero. I contend that there is no energy
flowing from the left half of the circuit to the right half. To
demonstrate this, compute the energy contributed by the battery on the
left. It is equal to the energy consumed by the resistor on the left.
Similarly for the battery and resistor on the rigtht. No energy flows
across the plane A-B.

If you still disagree, what is the power flowing across A-B?

....Keith