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Old June 9th 10, 08:44 PM posted to rec.radio.amateur.antenna
Roy Lewallen Roy Lewallen is offline
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First recorded activity by RadioBanter: Jun 2006
Posts: 1,374
Default Where does it go? (mismatched power)

Geoffrey S. Mendelson wrote:
If you have a resonant antenna, supposedly all of the power is radiated.

(SWR 1:1)

If you have a nonresonant antenna, some of the power is reflected back to
the transmitter.

(SWR 1:1)

If you connect a tuner and it is "tuned", none of the power is reflected
back to the transmitter.

(SWR at transmitter 1:1, at antenna still 1:1)

Obviously it has to go somewhere.

Where?

If you are designing a tuner, where would you design it to go?

Thanks in advance

Geoff.


All of the power produced by a transmitter is either radiated or
dissipated as heat, period. But you'll never understand where the
"reflected power" goes until you understand where it comes from.

Consider a 100 watt transmitter connected to a 50 ohm dummy load or
antenna via a half wavelength of 50 ohm lossless transmission line.

The transmitter sees an impedance of 50 ohms resistive.
The transmitter delivers 100 watts to the transmission line.
The transmission line delivers 100 watts to the load.
The load dissipates 100 watts.
The VSWR on the line is 1:1
The "forward power" in the transmission line is 100 watts.
The "reverse power" in the transmission line is zero.

Ok so far? Now replace the transmission line with one having 200 ohm
impedance.

The transmitter sees an impedance of 50 ohms resistive.
The transmitter delivers 100 watts to the transmission line.
The transmission line delivers 100 watts to the load.
The load dissipates 100 watts.
The VSWR on the line is 4:1.
The "forward power" in the transmission line is 156.25 watts.
The "reverse power" in the transmission line is 56.25 watts.

By changing the line impedance, we somehow created an extra 56.25 watts
of "forward power". Neither the transmitter nor the load was aware of
this wonderful event, since the transmitter sees the same load impedance
as before, and the load sees the same source impedance. The transmitter
is delivering exactly the same amount of power as before, and the load
is dissipating the same amount. (If the transmission line had loss, it
would have increased very slightly, but probably not enough to measure,
and certainly much, much less than 56 watts.)

Likewise, neither the transmitter nor the load knows anything about the
new "reverse power" which was created at the same time.

So the answer to your question is that the "reverse power" goes to
wherever the new excess "forward power" comes from. Once you figure out
where that is, you'll have a better understanding of the topic than
nearly everyone who has been arguing on this forum about it for years.

As for a tuner, it has the magical property of having different amounts
of "forward power" and "reverse power" at its input and output when the
amount of actual power flowing is the same on both sides (neglecting
tuner loss). So it can create or destroy "forward power" as well as
"reverse power" by a simple twist of its knobs. Little does the tuner,
transmitter, or load know that as soon as "reverse power" is created,
interminable arguments will take place debating about where it goes.

I now return you to your regularly scheduled programming. . .

Roy Lewallen, W7EL