Where does it go? (mismatched power)
On Jun 11, 4:18*pm, Cecil Moore wrote:
On Jun 11, 10:36*am, K1TTT wrote:
i wouldn't call it a 'virtual' impedance, it is a very real impedance.
Yes, it meets the (B) non-dissipative definition of impedance from
"The IEEE Dictionary". It doesn't meet the (A) dissipative definition
and it is not an impedor as it only exists as a V/I ratio. That's why
I call it a virtual impedance. There is no resistor, there is no
and that is part of the problem in here... 'you call it'. what is the
definition of 'virtual impedance' in the ieee dictionary?
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