On Jun 13, 2:04*pm, Cecil Moore wrote:
On Jun 13, 5:35*am, K1TTT wrote:

On Jun 13, 12:00*am, Cecil Moore wrote:
The answer to that question will reveal exactly what
happens to the reflected energy.

i don't care, i know that the superimposed voltage or current is
zero. *from that i can calculate the power or energy anywhere i
want. why does anyone care about 'energy' anyway, ...

You get exactly the same answers doing it my way but my way yields the
additional information of exactly what happens to the energy
components. When two wavefronts superpose to zero indefinitely, I
would take that as proof of interaction and wave cancellation.

This is what invariably happens to the discussion. After being told
that I am absolutely wrong about energy flow, I introduce the known
laws of EM physics from the field of optics and prove that they
provide exactly the same answers as a conventional RF analysis. After
some discussion, it is asserted that the person (not only you) doesn't
care and it doesn't matter anyway. W7EL says in his food-for-thought
article, "I personally don’t have a compulsion to understand where
this power 'goes'."

hams 'know' where the power goes, their swr meter tells them it goes
back to the transmitter!

why don't physicists working in optics calculate fields? the electric
and magnetic field models work just as well at those frequencies as
they do on hf. indeed, why don't optical physicists learn something
from rf designers and model their thin films with transmission lines!