Where does it go? (mismatched power)
On Jun 16, 12:09*pm, Owen Duffy wrote:
If the reflected wave was always, and entirely dissipated in Rs in that
type of source, then Prs=a+Vr^2/Zo=a+Vr^2/Rs (where a is some constant
value)... but it isn't, see the above expression.
Again, a straw man. To the best of my knowledge, nobody has said that
reflected power is "entirely dissipated in Rs" (except for the special
case when interference doesn't exist.)
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73, Cecil, w5dxp.com
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