On Jun 16, 4:44*pm, Roy Lewallen wrote:
Sorry, I don't think so. The very first equation, Vf=Vs/2, would be true
only if the load = Ro or for the time between system start and when the
first reflection returns.

I would really like to see you prove that assertion.
If Rs = 50 ohms and Z0 = 50 ohms, why would the reflected wave change
the forward power since the reflected wave sees a matched 50 ohm
"load"? Hint: The forward power won't change unless there is a re-
reflection at the source. You have deliberately designed your food-for-
thought example to avoid re-reflections at the source. Lumped-circuit
models seem to have atrophied a lot of brains.

Those are the kind of strange concepts that result from over-
simplification of the math models. When one denies the ExH energy
content of an EM wave (even a reflection) one chooses to follow
oneself down a primrose path. Optical physicists can track their light
wave energy down to the last photon. Why are some RF engineers so
ignorant in the tracking of energy that they assert there is no energy
in a reflected wave?
--
73, Cecil, w5dxp.com