On Jun 30, 7:24*am, Keith Dysart wrote:
Or are you saying that a step function does not have a Fourier
transform?

Your example has the step function disappearing during steady-state.
DC steady-state has no Fourier transform since omega equals zero. A
Fourier analysis requires a recurring function of the sum of sinusoids
involving integer multiples of omega*time. Your single step does not
recur so your conclusions are invalid.
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73, Cecil, w5dxp.com