On Dec 8, 1:52*pm, Sean Con wrote:
the displacement current raises resting particle neutralizing gravity
and
is in equilibrium.

Ok every one ..

the gausian field does result in maxwells equation. thats right.
VG
solar particles are attracted to diamagnetic surfaces ... I dont
VG
understand this. they have magnetic field lines frozen to them, if the
temperature is below some critical value, and are attracked bz other
magnetic field lines. thats a big story from MHD
Temperature is not involved. They form a skin
or boundary with hoop stress



some resistance leads to energy loss .. probably energy is being
converted to heat, not loss.
No energy conversion, they are at rest.


Current flows to a radiator skin --- farady said it should be so --
charge must move to outer surface

Excellent

for maximum efficiency particles must be raised due to friction
reasons.. most likely not.
they dont feel friction,
They must be placed in equilibrium otherwise you have a peeling action
that is a loss.
Now we have a single action and a equal reaction in place with no
losses.


but the do encounter collisions, and the emf is
supplied to overcome the unwanted energy conversion during collisions. *
Apparently particles in flight have a repelling force between them.
Either way the two vectors of current and displacement is applied
to the particle.
Now this particle does not take off with a parabolic curve and fall to
the ground because of gravity. The particle travels in a straight
line.
The two vectors applied to the particle are equal and opposite to
Gravity and the rotation of the Earth


They probably do not raise at surface because of efficiency issues, most
likely, as much as I know, they leave surface because ot surface is full
of electrons supplied from the electrode by the emf.
The electrons at rest are free electrons and are not part of the
substance or mass upon which they rest. An example is the skin upon
water which itself is a diamagnetic material. Place a magnet near the
skin and it will repel or bend the skin surface.

and the raising probably do not neutralize gravity, the field is putting.
The problem here is the word neutralize. Gravity enforces itself with
a vector that provides certain phenomina such as dragging a particle
to the ground. If one renders that vector neutral by an equal and
opposite force
then our little particle carrying a charge is not affect by gravity
and unless impacted by another vector or a magnetic field it will
continue to travel in a straight line.

a larger force than gravity on those particles.

I can imagine gravity being turned off, but for that i would expect the
force to arise from a mass field, or something which has no component
along gravity. Art, how do you be sure that this force is "turning off"
or neutralizing gravity, and not just "working against gravity"

You do not turn Gravity off! You can have a vector working against
gravity and in a loosing battle no less, but until that vector is
equal and opposite to gravity the effects of gravity cannot be said to
be neutralized. Remember, we are only relating to the vectors implied
upon the particle alone according to boundary rules.and the
"resultant" vector remains a straight line.

regards
s
Regards
Art