View Single Post
  #7   Report Post  
Old January 13th 11, 07:27 PM posted to rec.radio.amateur.antenna,sci.electronics.design
John - KD5YI[_3_] John - KD5YI[_3_] is offline
external usenet poster
 
First recorded activity by RadioBanter: Dec 2010
Posts: 54
Default Understanding Parallel to Series conversion

On 1/13/2011 11:05 AM, amdx wrote:
Hi All,
Please look at this in fixed font.
I'm looking for understanding of a series to parallel conversion for
antenna matching.
I'm pretty sure I'm missing something, so point it out to me.
This is in regard to a crystal radio, so the match is for a low impedance
antenna to a high impedance tank circuit.
The antenna: R=58 ohms C=1072 ohms at 1Mhz.
The tank: L=240uh C=106pf Q = 1000
Tank Z =~1.5 Mohms
Here's my understanding of what I think I'm reading.
I put a matching capacitor in series with the antenna.
Antenna-- -----R-----C--------Match cap-----tank------ground.
and this is supposed to transform the circuit to this.
( Maybe better said, equivalent to this)

l------------l
l l
Antenna--- R C LC---Tank
l l
l------------l
^
Ground

I calculate an 18.5pf cap for the match, making the antenna look like 58R
and 17pf.

So this; Antenna-- -----58R-----270pf--------Match
cap18.5pf-----1.5Mohms------ground.
This converts to;
l-----------------l
l l
Antenna---58R 17pf 1.5M---LC Tank at
l l Resonance
l-----------------l
^
Ground

And I now have a 1.5 Mohms source feeding a 1.5 Mohm load.
The purpose of which is to cause minimal loading of the tank by the antenna.
I don't understand how adding a series capacitor makes a parallel
conversion.
What do I misunderstand or do just need to believe the numbers.
Thanks, Mikek



At resonance, the LC tank disappears and you are left with a 1.5 Meg
equivalent of the tank losses.

Adding a small capacitance in series with your antenna gives you,
effectively, an antenna that looks like a 58R in series with a 17 pF
capacitor.

So now your circuit looks like:

58R---17pF-----|
|
1.5M
|
|
----
GND

I don't see any conversion at all.

John