On Feb 12, 9:15*am, "Szczepan Bialek" wrote:
Uzytkownik "Richard Clark" napisal w wiadomoscinews:n2pbl6h129opr3fres80nm3h8bt4e691vf@ 4ax.com...



wrote:
To be polarized must be the two poles (nodes)

The tip of a monopole and its base are its two nodes. A monopole is
polarized.

This is a very simple lesson to learn.

but, but, but, the base is a voltage minimum, not the opposite peak
voltage of the top!!! *how can that form two nodes to make the
electrons jump opposite directions? *this just can't be true! *this
must only be half polarity polarisation.

What? *Is this Oliver Twist in reverse polish notation?

"Please, sir, can I have another node?"

Yes, you have fully anticipated an objection in its juvenile form.
This can be countered (after asking for a hand to be held out for
switching):
Pick any potential reference point along the
length of the quarter wave monopole;
every point above it will have the opposite polarity
of any point below it - ergo, two nodes are described
each on either side of the reference.

Such situation is also close to the base. *But there no voltage. No voltage
no field emission. On the quarter wave monopole is only one place with very,
very high voltage. The dipole has the two.



I hope I don't have to explain that using batteries and resistors (it
may present a challenge in introducing advanced electronic concepts).

The "shape" of the node effects the emission. Thin wire radiate in different
direction than a hat .
But in the elongated node every point have the same polarity.

Faraday is great.
S*

but on the other half of the sine wave the polarity is reversed...
then what happens? do the electrons get sucked back in?