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Old February 16th 04, 01:22 PM
Roy Lewallen
 
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I don't have the pinout, but it should be easy to figure out with an
ohmmeter. Between two of the pins, measurements will show a diode. The
anode of this diode is the source, the cathode is the drain. The
remaining pin, which will measure open circuit in either direction to
the other two, is the gate.

Roy Lewallen, W7EL

Dallas Lankford wrote:
I would appreciate it very much if someone would send me the pin out for a
Siliconix VN66AK. Thank you, Dallas