On Tue, 10 May 2011 15:34:36 -0700 (PDT), Richard Fry
wrote:

So even if the RE-reflection from the source is lossless, and phase-
coherent with the original incident power at the load, how does this
yield the 100W of load dissipation that you posit?

The PI network between the tube and the output connector transforms
the tube Hi-Z to 50 Ohms (or any other suitable Z); however, the same
PI network's input Z (from the perspective of the returning, original
reflection) is NOT 50 Ohms, it is the complex conjugate (whatever 2:1
brings to the table) of the load answering phase-coherency, hence it
reflects the reflection (by the same mechanism of mismatch) to the
dissipative load the antenna, and thus into the æther.

The transmission line is bounded at either end by identical mismatches
in conjugation. There is a "ringing" in the line, which at only one
end there is dissipation (neglecting loss and damage to the tube for
exceeding maximum tolerances, of course).

73's
Richard Clark, KB7QHC