On 7/10/2012 1:05 PM, wrote:
Szczepan Bialek wrote:
"The current which flows on the outer surface of the shield is called common
mode current. In other words, it is the unbalanced current not returned
within the coaxial cable.
This leads to a very important question. If the current isn't returned in
the cable, where does it go? The answer is, it radiates! In fact, the amount
of radiation from the coax cable is directly proportional to the common-mode
current on that cable." From: http://www.k0bg.com/common.html

"In fact, the amount of radiation from the coax cable is directly
proportional to the common-mode current on that cable."

The currents consists of electrons.

Does it means that the electrons jump off from the end of the radiator?

No, it does not mean that.

There are no jumping electrons involved in radiation and you are an ineducable
idiot.


In Faraday time no such meters but Faraday had know that electrons (nuclei)
jump off from the end of the open circuit.

No, Faraday did NOT know that as it doesn't happen that way and you are
an ineducable idiot.

Also L. Lorenz known that the light is the oscillatory flow of electrons.

No, Lorenz did NOT know that as it doesn't happen that way and you are
an ineducable idiot.




I looked at my antenna the other day while I was talking. I saw some
jumping off. Szczepan has been right all along. Or maybe it was bird do
do I saw falling. Anyway, something was coming down from my antenna.

Michael