On Fri, 19 Nov 2004 08:26:54 -0500, "Dave VanHorn"
wrote:


Huh? It's only 5:30AM here and I just got up but, the ONLY time you
aren't consuming power is at the zero crossing of the voltage and
current sine waves (assuming a purely resistive load where I and E are
in phase). Since you are paying for power, which is P=I X E, during the
negative half cycle, you have, for example, -168 Volts X -1 Amp = +168
Watts...try it on a calculator...negative times a negative is positive.

P=I^2R, so which direction the current is flowing is irrelevant, as the
squaring removes any negatives, and R is always positive.

Would be interesting if you could get a true -R though! (not like a tunnel
diode, which just has a small region where increasing V decreases I, but
it's still positive)

---
Overunity?!

--
John Fields