View Single Post
  #12   Report Post  
Old March 5th 15, 01:50 AM posted to rec.radio.amateur.antenna
rickman rickman is offline
external usenet poster
 
First recorded activity by RadioBanter: Nov 2012
Posts: 989
Default Fish finder question?

On 3/4/2015 7:49 AM, Jeff wrote:

Connector impedance doesn't change with frequency, just as coax
impedance doesn't change with frequency. Loss will increase as
frequency increases, however.


Coax impedance certainly does change with frequency. Below about 500kHz
there is a significant slope with frequency.

At 200kHz a 50ohm cable may well look more like 100ohms and by the time
that you get to 1kHz it could be as high as 1kohm.

200kHz is in what is called the transition region and the impedance is
given by:

SQRT((R+j2pifL)/(C+j2pifC))

as opposed to the high frequency region where it is merely:

sqrt(L/C)

Below about 20kHz it changes again to SQRT(R/(j2pifC)

There are also other variables due to changes in the dielectric with
frequency and other losses.


Can you explain the above equations? In general it doesn't make sense
that the same effect would have different equations for different
frequencies. It does make sense though that the equations involved are
all simplifications of a single, more complex equation, optimized to
discount small effects over a given frequency range.

That said, I'm not sure I can see how these three equations can morph
into each other as f changes. The equation for the middle frequency
range seems to be the more encompassing so starting with that - if
frequency goes up enough the terms j2pifL and j2pifC dominate the R and
C terms and the equation simplifies to sqrt(L/C) appropriately.

But when f goes down enough, both terms shrink compared to R and C and
the equation would seem to simplify to sqrt(R/C) rather than
sqrt(R/j2pifC).

Is there possibly a typo in there somewhere?

--

Rick