On 7/4/2015 7:55 PM, Wayne wrote:


"Jeff Liebermann" wrote in message
...

On Sat, 04 Jul 2015 19:04:01 -0400, Jerry Stuckle
wrote:
Think of it this way, without the math. On the transmitter side of the
network, the match is 1:1, with nothing reflected back to the
transmitter.

So you have a signal coming back from the antenna. You have a perfect
matching network, which means nothing is lost in the network. The
feedline is perfect, so there is no loss in it. The only place for the
signal to go is back to the antenna.

Wikipedia says that if the source is matched to the line, any
reflections that come back are absorbed, not reflected back to the
antenna:

https://en.wikipedia.org/wiki/Impedance_matching
"If the source impedance matches the line, reflections
from the load end will be absorbed at the source end.
If the transmission line is not matched at both ends
reflections from the load will be re-reflected at the
source and re-re-reflected at the load end ad infinitum,
losing energy on each transit of the transmission line."

Well, I looked at that section of the writeup.
And, I have no idea what the hell they are talking about.
Looks like a good section for a knowledgeable person to edit.

What is not clear about your objection. I can't say for sure if it is
accurate, but it seems clear to me saying that at either end if you have
an impedance mismatch some of the wave will be reflected. With
mismatches at both ends the wave will bounce back and forth losing
energy each time, but never dying out completely. That is exactly what
I would expect.

The only case I am aware of that will give total reflection is when the
terminal is open circuit with infinite impedance absorbing *no* signal.

--

Rick