Dave Shrader wrote:

J Koli wrote:

Hw can I construct 110 deg phasing line for 3.8mhz? 450 ohm window type
ladder line preferred.

This is for 2 dipoles each 121' long and 70' apart. Height above avg
ground 60'. I would like to feed 1 dipole 110 deg out of phase of the
other..

Jay NE2Q


110/360 = 0.305 wavelength
0.305 wavelength * 0.95 velocity factor = 0.2897 wavelength in ladder line.

300,000,000 meters/ 1800000 Hz = 166.67 meters free space wavelength.

166.67 * 39.37 / 12 = 546.8 feet.

So, 0.2897 * 546.8 = 155.48 ~ 158.4 feet.

But please note that doesn't balance the currents except by
sheer accident. I'll bet he wants balanced currents.
--
73, Cecil http://www.qsl.net/w5dxp



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