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Old September 15th 03, 08:20 AM
Ryan, KC8PMX
 
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Yep, and I didn't see it specifying whether it was a half-wave or not.
Regardless of the fact I DO know how to calculate it or any fraction of a
full wavelength.

If the question was "What is the length of a quarter-wave dipole for
14.240Mhz?" or "What is the length of a half-wave dipole for 14.240Mhz?" or
whatever then I would have answered right of the bat. Yeah, it is simple to
do that formula, but to give the answer would be hard unless you gave ALL of
the possibilities such as below:


one-sixteenth wave @ 14.240Mhz = 4.108146
one-eighth wave @ 14.240Mhz = 8.216292
three-sixteenth wave @ 14.240Mhz = 12.324438
quarter-wave @ 14.240Mhz = 16.432584
five-sixteenth wave @ 14.240Mhz = 20.54073
three-eighths wave @ 14.240Mhz = 24.648876
seven-sixteenths wave @ 14.240Mhz = 28.757022
half-wave @ 14.240Mhz = 32.8651685
nine-sixteenths wave @ 14.240Mhz = 36.973314
five-eighths wave @ 14.240Mhz = 41.08146
eleven-sixteenths wave @ 14.240Mhz = 45.189606
three-quarter wave @ 14.240Mhz = 49.297752
thirteen-sixteenths wave @ 14.240Mhz = 53.405898
seven-eigths wave @ 14.240Mhz = 57.514044
fifteen-sixteenths wave @ 14.240Mhz = 61.62219
full wave dipole @ 14.240Mhz = 65.730337


All of the above answers would be correct (barring accidental typos), but
the original poster of the question in the first place DID NOT SPECIFY.
See, it is important, unless you consider ALL antennas to be exactly
one-half wavelength in length.



--
Ryan, KC8PMX
FF1-FF2-MFR-(pending NREMT-B!)
--. --- -.. ... .- -. --. . .-.. ... .- .-. . ..-. .. .-. . ..-.
... --. .... - . .-. ...


As you know from studying for your Technician license (and the material

also
appears in the General study guide), you can calculate the length of your
half-wave dipole directly knowing only the frequency. The equation is:

Length in feet = 468 divided by the frequency in megahertz.

Also from these same study guides, you can calculate the wavelength by the
following equation.

Wavelength in meters = 300 divided by the frequency in megahertz
(of course if you wish you can then convert the answer to feet).


Dee D. Flint, N8UZE