"Cecil Moore" wrote in message
. ..
Owen Duffy wrote:
Cecil Moore wrote:
Reg, I'm curious how you would solve this stub problem
without a Smith Chart.

| 45 deg | 45 deg |
Source====Z01=========Z02====open

Stub sections are lossless. Z01 = 600 ohms and is 45
degrees long. Z02 = 50 ohms and is 45 degrees long.
What is the impedance looking into the stub from the
source?

I missed the significance of this problem Cecil.

Is it principally a theoretical (being lossless) problem that a Smith
chart can solve, or does it have some other significance?

It's just a mental exercise with a hidden significance. This
is the type of problem that I would solve with a Smith Chart.

How about a solution? What impedance does the source see? The
physical length of the stub is 90 degrees. What is the electrical
length of the stub in degrees?
--
73, Cecil http://www.qsl.net/w5dxp

Hi Cecil

Is it posible that the length of the "stubs" change? I'd have thought the
length of the stub is always the same. 45 degrees should always be 45
degrees, shouldnt it?? An open circuit, 45 degrees back along a 50 ohm line
looks like 50 ohms capacitive. That 50 ohms looks like something like 500
ohms inductive as viewed 45 degrees back along a 600 ohm line.
I'd guess your point is that 500 ohms of pure inductive reactance is never
seen 90 degrees back from an open, no matter what the Zo of the line

Jerry