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#1
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Cecil,
I think you are conflating models with nature, and trying to champion one correct model over another correct model! It's confusing to onlookers and boring. There is NO inconsistency between saying "there's only one electromagnetic field in a transmission line" and "a circulator seperates the forward wave from the reflected wave" if you've suitably defined what all those terms mean and you do the correct math. The electromagnetic field as a function of space and time in the coaxial transmission line is a three-dimensional time dependent field. There's a description wherein one single vector valued function E(r,phi,z, t) describes the electric field and another describes the magnetic field, and of course, you can get one from the other, so in some sense, all you need to describe what's going on is E(r,phi,z,t). Now, in the coaxial TEM mode the radial and azimuthal dependence of the fields becomes trivial, and you're just left with some function E'(z,t) to describe the electric field, and one B'(z,t) for the magnetic field (once again, you can of course, get one from the other) It turns out that mathematically you can represent this function as a superposition of other functions, forward and reverse traveling waves. It's just a DIFFERENT WAY OF WRITING IT DOWN. A circulator *doesn't know math*. Its operation may have a simple description in the language of forward and reverse waves, but it does what it does no matter what model you use to describe it. If you get different answers using a forward and reflected wave description than some other description, then one or both of your descriptions are wrong. The conversion of one mathematical description of the electromagnetic field into a series of statements in English and the argument based on those words never gets you anywhere on this topic. Why not pick up a copy of Jackson's Electrodynamics and write down what you're trying to say mathematically. If you're right, everyone will have to be convinced. 73, Dan |
#3
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Hey Cecil,
Can you sum up the problem with conservation of energy that modern RF textbooks get wrong? Dan |
#4
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wrote:
Can you sum up the problem with conservation of energy that modern RF textbooks get wrong? They don't get it wrong - they just don't discuss it at all. But here is an example of the problem: http://eznec.com/misc/food_for_thought/ First article - last paragraph. W7EL considers steady-state conditions while ignoring the previous transient state conditions. He implies that the energy in the reflected wave cannot be recovered but it is indeed dissipated as power in the system after power is removed from the source. The source supplies exactly the amount of energy during the transient power up conditions needed to support the forward and reflected waves during steady-state. This is easy to prove. But W7EL's Ivory Tower protects Him from peons like me. -- 73, Cecil http://www.qsl.net/w5dxp |
#5
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The net power flux in the line gets smaller as the reflected wave gets
stronger while maintaining a constant electric field (constant voltage as in Roy's example). If you can match to the new impedance at the line input; that is, make the electric fields both stronger, you can get a larger net power flux even in the presence of some elevated SWR. See LaTeX formatted math at http://en.wikipedia.org/wiki/User ![]() The flux of stored power in the line, interestingly enough, is a sinusoidal function of position. I'm still thinking what to make of it, but I thought I'd post the math for people to look at (and check, please!!!!) ... I'll be back later. 73, Dan |
#6
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#7
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Cecil Moore wrote:
If I understand correctly, Roy's argument is that since the source is not supplying any steady-state energy to the lossless stub, there is no energy in the reflected wave within the stub. That sounds right... if the reflection coefficient is 1 then there's no net power flux into/through the line in steady state, and this can be described if you like by counterpropagating waves each carrying the same amount of energy. The problem is, in your other example where you say 200 joules in the forward wave + 100 joules in the reflected wave = 300 joules in the line total, you're neglecting the vector character of the power flux. Yes, the waves carry energy, but they carry it in different directions. The net power flux in the line with 200W forward power and 100W reflected power is 100W net power flowing to the load from the source. The real part of the Poynting vector of the reflected wave opposes that of the forward wave, as long as I got all the signs right. I don't think we can neglect the imaginary part of the Poynting vector, though. It's not zero and I think it represents the flow of the power in the stored fields in the line, and if we want to get the total energy in the line, we have to include the stored fields. Dan |
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