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Hello,
I'm not sure whether I have a good picture of your situation but there are some general rules. In general, magnetic field lines generated by the loop that are parallel with the wire from the inverted V, do not induce voltage into the wire. On the other hand when the E-field lines are perpendicular to the V's wire, there will be no induced voltage in the wire. Imagine a plane that cuts your loop (inclusive the tuning capacitor) into half. The loop is perpendicular to the plane. Every wire that passes along or inside the loop and stays in that symmetry plane obeys the above statement, and interaction will be negligible. The above is valid when you loop is fed fully balanced (no common mode current on feed line). When you use the V, the loop will introduce some capacitance to the V. It is best to keep the wire away from the high voltage ends (where the tuning capacitor may be present), because a slight deviation from the symmetry plane will cause interaction between the loop and the wire. Besides this general rule, also wires running close or through the loop, but off the symmetry plane may be acceptable, but prediction is difficult. You are able to measure the effect. When you make a kind of common mode (current) transformer with a diode detector (with a suitable ferrite the you can place around the feed line), you are able to detect the common mode current (when transmitting). If you run the questionable wire of your V through or along the loop and the output of your transformer does increase significantly, there is (undesirable) interaction. I hope this will help you. Best Regards, Wim PA3DJS |
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