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Owen Duffy wrote:
Having regard for the sign of the traveling waves, the only solution to those constraints / conditions is that the reflected travelling wave must have zero amplitude. Sorry Owen, that's not true. Assuming a 1/2WL dipole, the reflected voltage has traveled 180 degrees. The reflected current has traveled the same 180 degrees plus experienced a 180 degree phase shift at the tip of the dipole. Assuming 100 watts is being applied to the antenna, the following conditions satisfy the observed conditions on the dipole at the feedpoint. Pfor = 500W, Vfor = 548V, Ifor = 0.91A Pref = 400W, Vref = 490V, Iref = 0.81A Pnet = 100W, Vnet = 58V, Inet = 1.72A You talk of the "reflected wave" as if it has inertia, that it must keep travelling when it reaches the junction of the feedline and the antenna? You are not alone in speaking that way, but thinking that way will get in the way of understanding what is happening. It is well known that all EM waves contain energy and momentum (inertia) so David is correct. The thing that reverses the momentum of the reflected wave is destructive interference at the Z0-match point. Anyone interested in understanding how/why it happens is invited to peruse my energy analysis article at: http://www.w5dxp.com/energy.htm -- 73, Cecil http://www.w5dxp.com |
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