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#1
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"Owen Duffy" wrote
The mechanism is not "that the reflected wave must travel back to the PA anode and will be absorbed there causing overheating". Take an example of the 50 ohms load discussed, and an electrical half wave of 70 ohm line connected to a transmitter designed for a 50 ohm load. The transmitter behaves exactly as if that line were 50 ohms. Though there is a reflected travelling wave on the line, it does not travel back to the PA anode where it is absorbed and converted to heat. ____________ Really, the mechanism is there -- only the unique circumstance you describe protects the PA from seeing reflected power in such cases. Other line lengths in this scenario could stress PA components beyond their ratings. And even if the PA saw no reflected power because of a fortunate length of transmission line connecting it to a mismatched antenna/load, that reflected power still exists in the transmission line, and may cause its failure. Manufacturers of the rigid coaxial line used in broadcast stations (e.g., Dielectric) require derating its maximum power rating inversely by the value of the SWR existing in it . A power derating factor related to SWR also applies to Andrew Heliax® and RG-type coax line. Deliberately setting up, or tolerating reflected power on a transmission line is not done without risk. RF |
#2
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Richard Fry wrote:
Really, the mechanism is there -- only the unique circumstance you describe protects the PA from seeing reflected power in such cases. Other line lengths in this scenario could stress PA components beyond their ratings. Yes, the exposure of the PA to reflected power depends upon the phase of the reflected wave referenced to the phase of the source wave. SWR doesn't tell the whole story because phase is not reported by the SWR measurement. What is happening with 1/2WL of Z0=600 ohm feedline connected to a 50 ohm load on one end and a 50 ohm source on the other end is interference. Destructive interference toward the source causes constructive interference toward the load and the reflected energy at the source is re-directed back toward the load. What we want to avoid in our antenna systems is constructive interference toward the source. -- 73, Cecil http://www.w5dxp.com |
#3
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"Cecil Moore"
What is happening with 1/2WL of Z0=600 ohm feedline connected to a 50 ohm load on one end and a 50 ohm source on the other end is interference. Destructive interference toward the source causes constructive interference toward the load and the reflected energy at the source is re-directed back toward the load. What we want to avoid in our antenna systems is constructive interference toward the source. ______________ Whether the source sees that reflected power or not, that reflected power is stressing the transmission line -- regardless of the electrical length of that line at the operating frequency. IOW, for these unique conditions the source may be unaffected by the reflected power in the line, but the line itself is still stressed by that power -- and possibly to the point of failure. RF |
#4
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Richard Fry wrote:
Whether the source sees that reflected power or not, that reflected power is stressing the transmission line -- regardless of the electrical length of that line at the operating frequency. Didn't mean to imply that I was disagreeing with you in any way. Given the forward and reflected power readings for any particular line, the stresses can be calculated. -- 73, Cecil http://www.w5dxp.com |
#5
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On Tue, 5 Sep 2006 06:48:57 -0500, "Richard Fry"
wrote: "Owen Duffy" wrote The mechanism is not "that the reflected wave must travel back to the PA anode and will be absorbed there causing overheating". Take an example of the 50 ohms load discussed, and an electrical half wave of 70 ohm line connected to a transmitter designed for a 50 ohm load. The transmitter behaves exactly as if that line were 50 ohms. Though there is a reflected travelling wave on the line, it does not travel back to the PA anode where it is absorbed and converted to heat. ____________ Really, the mechanism is there -- only the unique circumstance you describe protects the PA from seeing reflected power in such cases. Other line lengths in this scenario could stress PA components beyond their ratings. Richard, There is not such a mechanism in the general case, the example I gave shows that the reflected wave does not necessarily travel back to the source where it is absorbed. If you re-read my words "Next thing, you will be thinking that the reflected wave must travel back to the PA anode and will be absorbed there causing overheating." Remembering the context was a wave on the dipole reflected from the o/c end, and the word "must" was used to mean "necessarily". Sure,transmission lines with VSWR may transform impedance, have higher losses (if they are long enough), operate at higher voltages in places (if they are long enough), operate with higher currents in places (if they are long enough). Nothing I have said is in conflict with that or suggests otherwise. Transmitters operated at other than their rated load impedance may operate at higher voltages, higher currents, different power etc and may damage components. Nothing I have said is in conflict with that or suggests otherwise. But, the mechanism is not that the reflected wave *necessarily* travels all the way back to the PA anode by virtue of some kind of momentum (as sometimes expressed by some amateurs). In the case raised by the OP, the reflected wave on the dipole and the forward wave resolve (as in resolution of phasors) to an impedance of 50+j0 (OP's hypothetical example), and the constraints / conditions at the feedline / feedpoint junction are fully satisfied with no reflected wave on the feedline. (I used the term resolve, Cecil must call it destructive interference.) The reflected wave on the dipole does not have a momentum that *must* carry it to the PA anode to be absorbed there. Owen -- |
#6
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"Owen Duffy" wrote:
But, the mechanism is not that the reflected wave *necessarily* travels all the way back to the PA anode by virtue of some kind of momentumne / feedpoint junction are fully satisfied with no reflected wave on the feedline. (I used the term resolve, Cecil must call it destructive interference.) The reflected wave on the dipole does not have a momentum that *must* carry it to the PA anode to be absorbed there. _____________ However, any amount of reflected power from the termination at the far end of a transmission line has a greater chance of damaging tx PA components, and of stress/failure to the transmission line itself than if the reflected power from the antenna/load was zero, regardless of the electrical length of said transmission line. This reality of physics is not subject to debate, don't you agree? RF |
#7
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On Tue, 5 Sep 2006 18:04:36 -0500, "Richard Fry"
wrote: "Owen Duffy" wrote: But, the mechanism is not that the reflected wave *necessarily* travels all the way back to the PA anode by virtue of some kind of momentumne / feedpoint junction are fully satisfied with no reflected wave on the feedline. (I used the term resolve, Cecil must call it destructive interference.) The reflected wave on the dipole does not have a momentum that *must* carry it to the PA anode to be absorbed there. _____________ However, any amount of reflected power from the termination at the far end of a transmission line has a greater chance of damaging tx PA components, and of stress/failure to the transmission line itself than if the reflected power from the antenna/load was zero, regardless of the electrical length of said transmission line. If it makes you more comfortable to restrict your solutions to those with flat lines (VSWR~=1) then that is ok with me, but that does not invalidate other approaches. Antenna systems incorporating lines with high VSWR do not necessarily subject the PA components to any different risk, or transmission lines to excessive stresses, it is a matter of design... and the design is more complex than buying a tx intended for 50ohm load, some 50ohm coax and a 50ohm antenna and plugging them all together. Owen -- |
#8
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Richard Fry wrote:
However, any amount of reflected power from the termination at the far end of a transmission line has a greater chance of damaging tx PA components, and of stress/failure to the transmission line itself than if the reflected power from the antenna/load was zero, regardless of the electrical length of said transmission line. This reality of physics is not subject to debate, don't you agree? Suppose I have a 50 ohm antenna fed with a one wavelength, 50 ohm transmission line. No reflected power, no damage. Now I replace the 50 ohm one wavelength line with a 300 ohm one wavelength line. For 100 watts delivered to the load, the forward power on the line is 204 watts and the reverse power is 104 watts. All that reverse power could do a lot of damage, then? So I guess I should replace the 50 ohm load with a 300 ohm one. Then there won't be any reflected power, and the transmitter should be ok. Right? After all, it's physics. Roy Lewallen, W7EL |
#9
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Roy Lewallen wrote:
Now I replace the 50 ohm one wavelength line with a 300 ohm one wavelength line. For 100 watts delivered to the load, the forward power on the line is 204 watts and the reverse power is 104 watts. All that reverse power could do a lot of damage, then? Probably not at that power level but try this: Let's say the power handling limit for the 300 ohm line is 1000 watts under matched line conditions. We are delivering 1000 watts to the 50 ohm load. The forward power on the 300 ohm line is 2040 watts and the reverse power on the 300 ohm line is 1040 watts. Yes indeed, the reflected power can cause the 300 ohm line to burn up which is the point Richard Fry was trying to make. -- 73, Cecil http://www.w5dxp.com |
#10
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"Roy Lewallen" wrote
Suppose I have a 50 ohm antenna fed with a one wavelength, 50 ohm transmission line. No reflected power, no damage. Now I replace the 50 ohm one wavelength line with a 300 ohm one wavelength line. For 100 watts delivered to the load, the forward power on the line is 204 watts and the reverse power is 104 watts. All that reverse power could do a lot of damage, then? So I guess I should replace the 50 ohm load with a 300 ohm one. Then there won't be any reflected power, and the transmitter should be ok. Right? ___________ As you well know, the system change you describe will not remove all reflected power seen at the output of a tx expecting a 50 ohm load. You have simply moved the source of the reflection back to the plane of the tx output connector. Under your scenario the transmission line is happy, but the tx - not so much. RF |
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