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On Feb 23, 7:06 am, Scott wrote:
So, hows does an armchair operator (one who doesn't have $10K worth of test equipment) determine the efficiency of the antenna? Scott N0EDV Dave wrote: YES! You are reading the rules correctly. There are many 60 meter mobiles running 300 to 400 watts into a 10% efficient antenna relative to a 1/2 wavelength dipole. Get on 60, It;s is a great band. Cecil Moore wrote: 60m operation is limited to 50w pep relative to a 1/2WL dipole. Since a typical 60m mobile antenna would be much less than 50% efficient, seems it would it be OK to run an IC-706 at its normal 100 watt output level. Am I reading the rules right?- Hide quoted text - - Show quoted text - Hmmm, one could go to Terman, et. al... Lots of heavy math... ughhhh One could ask the mobile whip manufacturer what the relative gain of his product is - On second thought that's unlikely to get an answer other than 42... (See: HitchHikers Guide To the galaxy) Or one could do the bone simple, farm boy stupid, yet amazingly effective method of comparing the relative length of the mobile whip to a quarter wave vertical... First, the quarter wave vertical is half the length of a dipole so you immediately have a multiplier of 2... (Awwww right you nit pickers, DOWN! - Yes I know about vertical-P loss compared to horizontal-P, but I'm farm boy simple for this one) Assume the 1/4 Lambda vertical is 45 feet (rough number, I'm a farm boy, remember) and the whip is 8 feet... Then 45/8 = 5.6 ratio... So 2 times 5.6 = 11.2 ratio so far... Therefore 11.2 times 50w = 284 watts... Now the efficiency of a mobile whip that is just over 20% tall (of a quarter wave) is roughly 8%-10% (swag) Lets call it 10% for rough numbers therefore we can expand the 284 watts by dividing 0.1 into it... or 2840 watts.... Which will make your IC-706 sweat a bit... OK nitpickers, have fun... denny / k8do |
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