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tuner - feedline - antenna question ?
Cecil Moore wrote in news:QeJEh.2909$8x.1740
@newssvr14.news.prodigy.net: Owen Duffy wrote: Cecil, it seems that between the two of you, you are constructing a picture that (in a lossless line for simplicity) if the Bird 43 reads 100W forward and 50 watts reflected, the power radiated (ignoring antenna ohmic losses) is 100W, but 50W is reflected toward the transmitter... but that's allright because the 50W will be reflected by a Zo matched PA, and energy is conserved on the line. Please don't insult our intelligence. If the Bird reads Of course it is nonsense, but it is a logical development based on Jeff's words "What you are describing could be called 'transmitted' power or power delivered into a mismatched load, but that it different from forward power, or the power delivered by the source" and your words "For systems Z0-matched by an antenna tuner, the situation becomes trivial to understand. The reflected energy is re-reflected by the Z0-match provided by the properly tuned antenna tuner". The steady state solution of the ratio of V/I at the input to a real transmission line section (ie lossy) that has a load of some arbitrary impedance is solved using equations that do not include forward and reflected power terms. The power at any point is the real part of V*conjugate(I) at that point, no matter whether it is at the source, load, line input, output or anywhere along the line. Owen |
tuner - feedline - antenna question ?
On Mon, 26 Feb 2007 20:38:00 GMT, Owen Duffy wrote:
The danger in the "power is refelected at a mismatch" explanation, is that it follows that power reflected at a mismatched antenna flows back toward the transmitter and is at least partially absorbed in the PA as heat. Though that is a popular belief, it is not supported by fact. Hi Owen, This denies experience. 73's Richard Clark, KB7QHC |
tuner - feedline - antenna question ?
Owen Duffy wrote:
Of course it is nonsense, but it is a logical development based on Jeff's words ... Please don't blame me for someone else's words. The irradiance (power) equations from optical engineering for the combining of electromagnetic power from two EM waves are accepted as a fact of physics. Do you really think that the amateur radio community should reject that fact of physics? -- 73, Cecil http://www.w5dxp.com |
tuner - feedline - antenna question ?
Richard Clark wrote in
: On Mon, 26 Feb 2007 20:38:00 GMT, Owen Duffy wrote: The danger in the "power is refelected at a mismatch" explanation, is that it follows that power reflected at a mismatched antenna flows back toward the transmitter and is at least partially absorbed in the PA as heat. Though that is a popular belief, it is not supported by fact. Hi Owen, This denies experience. Do you mean the experience that the PA may (but not necessarily) run hotter on other than its rated load impedance? Could that be exlained without introducing transmission lines and the reflected power issue by examining how the PA works on a load different to its rated load? I suggest that if a PA / line / load situation transforms the actual load to some arbitrary impedance Z at the PA end of the line, the PA will peform exactly as if the PA were directly loaded by a lumped constant load of Z. The explanation of any heating effects or changed operating voltages is in the effect of the load impedance Z (however it is obtained) on the PA. Does that make sense? Owen |
tuner - feedline - antenna question ?
Owen Duffy wrote:
I suggest that if a PA / line / load situation transforms the actual load to some arbitrary impedance Z at the PA end of the line, the PA will peform exactly as if the PA were directly loaded by a lumped constant load of Z. Yes, that is true for the performance of the PA. Certainly not true for the performance of the transmission line or antenna. My favorite quotation by an antenna guru on this newsgroup is that "a 50 ohm antenna can be replaced by a 50 ohm resistor without changing anything". If that were true, we don't need antennas. :-) I'm going to be away from my computer for 48 hours. -- 73, Cecil http://www.w5dxp.com |
tuner - feedline - antenna question ?
Cecil Moore wrote in
: Owen Duffy wrote: Of course it is nonsense, but it is a logical development based on Jeff's words ... Please don't blame me for someone else's words. A selective partial quotation to misrepesent what was actually written Cecil! Owen |
tuner - feedline - antenna question ?
Cecil Moore wrote in
t: Owen Duffy wrote: I suggest that if a PA / line / load situation transforms the actual load to some arbitrary impedance Z at the PA end of the line, the PA will peform exactly as if the PA were directly loaded by a lumped constant load of Z. Yes, that is true for the performance of the PA. Certainly not true for the performance of the transmission line or antenna. Please explain? Owen |
tuner - feedline - antenna question ?
On Mon, 26 Feb 2007 23:24:13 GMT, Owen Duffy wrote:
Could that be exlained without introducing transmission lines and the reflected power issue by examining how the PA works on a load different to its rated load? Hi Owen, Let's treat this like the Chinese Box problem. If you didn't know what the load was, could you explain it any differently? No. Apriori knowledge is not a proof. 73's Richard Clark, KB7QHC |
tuner - feedline - antenna question ?
Richard Clark wrote in
: On Mon, 26 Feb 2007 23:24:13 GMT, Owen Duffy wrote: Could that be exlained without introducing transmission lines and the reflected power issue by examining how the PA works on a load different to its rated load? Hi Owen, Let's treat this like the Chinese Box problem. If you didn't know what the load was, could you explain it any differently? No. Apriori knowledge is not a proof. Richard, I content that: - the power output of the PA; and - the efficiency of the PA may be (and usually are) sensitive to the load impedance. A steady state analysis is usually adequate for most ham radio applications, though there may be cases where establishment of steady state brings its own issues. This discussion is about the steady state. Though it is often asserted that the PA will get hotter as a result of "reflected power" being dissipated in the dynamic output impedance of the PA, and that this may / will damage the PA, the power explanation doesn't work numerically in the general case. The constrained ratio of V/I is an aspect of the field setup in a transmission line, and the launching of a reflected wave to reconcile the load V/I with the constrained (Vf+Vr)/If-Ir) at the load end of the line is a solution for what happens on the transmission line. At the source end of the line, (Vf+Vr)/If-Ir) at that point (a function of (Vf+Vr)/If- Ir at the load end, and the complex propagation coefficient and Zo of the line) give us the equivalent (complex) impedance seen by the PA, and we can predict / explain the behaviour of the PA (maximum power out, efficiency) on that equivalent load. This method of analysis does work numerically. Owen |
tuner - feedline - antenna question ?
On Tue, 27 Feb 2007 01:07:12 GMT, Owen Duffy wrote:
Richard Clark wrote in Let's treat this like the Chinese Box problem. If you didn't know what the load was, could you explain it any differently? No. Apriori knowledge is not a proof. Richard, I content that: Contend or offer in contention. - the power output of the PA; and - the efficiency of the PA may be (and usually are) sensitive to the load impedance. This is not contending nor contention and is content only for a non sequitur. The line following a tuner exhibits considerable loss (poor efficiency) that can only occur on the basis of power and mismatch. You yourself offered in other correspondence that it exceeds cable attenuation specifications found only in a matching condition. To suggest that a PA's sensitivity is somehow exhalted in the face of identical, ordinary behavior of a passive component is hardly seperable. Consider the simple substitution to your quote: - the power output at the terminus of the line; and - the efficiency at the terminus of the line may be (and usually are) sensitive to the load impedance. continuing on... A steady state analysis is usually adequate for most ham radio applications, though there may be cases where establishment of steady state brings its own issues. This discussion is about the steady state. I expressed nothing of transitory behavior. Though it is often asserted that the PA will get hotter as a result of "reflected power" being dissipated in the dynamic output impedance of the PA, and that this may / will damage the PA, the power explanation doesn't work numerically in the general case. Heat is the outward proof of power and is always demonstrable in both specific and general cases. Occurrences of other, significant radiation from the source (as long as that source physically occupies a substantially minor region of wavelength) is exceedingly difficult to achieve. You don't offer a numerical proof of a general case, and given that the general case must allow for the specific cases already allowed in your discussion above - that may be an untenable assertion for you. Those specific cases are demonstrably caloric and must follow the same math you suggest. I suspect you are trying to argue differences by degree (no pun intended as to heat); but I seriously doubt you can produce the math to do that. The arguments that flow from that involve what is called source resistance, and those arguments are legion in this forum (where naysayers embrace a refusal to accept or name ANY value - a curious paradox and an engineering nihilism I enjoy to watch). 73's Richard Clark, KB7QHC |
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