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#1
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All,
I am trying to install a trapped 40m dipole in the attic, the antenna is in place however it is short and resonates at about 7.7 MHz. I decided to try it by using a tuner close to the transmitter in the shack. The feedline is 50 ohm coax. On low power the tuner creates a very low SWR. The transmitter is a solid state 100 watt Heathkit. However when I transmit according to the SWR Watt meter the system appears to transmit well over 200 watts. It pined the meter on a 200 watt range. I repeated the test twice and then stopped. When it is transmitting the SWR reads about 1.1 to 1. The meter works very well and does not exhibit strange readings on other setups. My questions a What is happening? What is causing it? Thanks - Dan |
#2
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dansawyeror wrote:
I am trying to install a trapped 40m dipole in the attic, the antenna is in place however it is short and resonates at about 7.7 MHz. I decided to try it by using a tuner close to the transmitter in the shack. The feedline is 50 ohm coax. On low power the tuner creates a very low SWR. The transmitter is a solid state 100 watt Heathkit. However when I transmit according to the SWR Watt meter the system appears to transmit well over 200 watts. It pined the meter on a 200 watt range. I repeated the test twice and then stopped. When it is transmitting the SWR reads about 1.1 to 1. The meter works very well and does not exhibit strange readings on other setups. My questions a What is happening? What is causing it? When the transmitter is putting out 100 watts and the forward power reading is 200 watts, it means that the SWR is 5.83:1, i.e. the voltage reflection coefficient is 0.707 and the power reflection coefficient is 0.5. To get the power delivered to the load, you must subtract reflected power from forward power. In your case that seems to be: Pfwd - Pref = Pload = ~Psource 200w - 100w = 100w = ~100w -- 73, Cecil http://www.w5dxp.com |
#3
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In article ,
Cecil Moore wrote: dansawyeror wrote: I am trying to install a trapped 40m dipole in the attic, the antenna is in place however it is short and resonates at about 7.7 MHz. I decided to try it by using a tuner close to the transmitter in the shack. The feedline is 50 ohm coax. On low power the tuner creates a very low SWR. The transmitter is a solid state 100 watt Heathkit. However when I transmit according to the SWR Watt meter the system appears to transmit well over 200 watts. It pined the meter on a 200 watt range. I repeated the test twice and then stopped. When it is transmitting the SWR reads about 1.1 to 1. The meter works very well and does not exhibit strange readings on other setups. My questions a What is happening? What is causing it? two things pop into mind could be your antenna is radiating towards and into or near your radio and causing some feedback that might effect the radio and or the meter there is also the possibility that you have some bad (common mode? etc) current flowing back down the coax which could also wreck havock just my guess and double check the above and grounds put a dummy load into your tuner see if you get proper readings |
#4
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To get the power delivered to the load, you must subtract
reflected power from forward power. In your case that seems to be: Pfwd - Pref = Pload = ~Psource 200w - 100w = 100w = ~100w How can that be? If the meter is basically a directional coupler then the forward power is just that. Subtracting any reflected power will just give a stupid answer. The only errors will be due to the directivity of the coupler, which will give a band of uncertainty which varies with VSWR, and the error due to the accuracy of the detectors. My Bird does not subtract any reflected power to give a forward power reading!! It can't I need to rotate the slug to read reverse power. 73 Jeff |
#5
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"Jeff" wrote in
.com: How can that be? If the meter is basically a directional coupler then the forward power is just that. Subtracting any reflected power will just give a stupid answer. The only errors will be due to the directivity of the coupler, which will give a band of uncertainty which varies with VSWR, and the error due to the accuracy of the detectors. My Bird does not subtract any reflected power to give a forward power reading!! It can't I need to rotate the slug to read reverse power. Jeff, without commenting on whether Cecil's assertions are right or wrong, you seem to have some misconceptions about what is measured with your Bird (presumably 43). The so called "forward power" and "reflected power" are notional values, but not actual power "components". The only power is the average rate at which energy passes a point, and it is in one direction or the other. In fact the power can be calculated taking "forward power" minus "reflected power", but only in the case where the sampler is calibrated for Zo being real (as it is in a Bird 43). My article at http://www.vk1od.net/VSWR/VSWRMeter.htm describes the operation of a Bruene type of VSWR meter and discusses the power measurement issue. Though the sampler in the Bird is different to the Bruene sampler, the Bird samples V and I in a very small region ( regarded a point ) and sums them in the same way as the Bruene circuit. Owen |
#6
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The so called "forward power" and "reflected power" are notional values,
but not actual power "components". The only power is the average rate at which energy passes a point, and it is in one direction or the other. I am sorry, but I disagree, forward power is real and can be measured, or if you wish separated out with a circulator or isolator. What you are describing could be called 'transmitted' power or power delivered into a mismatched load, but that it different from forward power, or the power delivered by the source. 73 Jeff |
#7
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On Mon, 26 Feb 2007 10:25:10 -0000, "Jeff" wrote:
I am sorry, but I disagree Hi Jeff, Your appologies aside, it is the convention you are disagreeing with. The injection of such terminology as 'transmitted' power is not part of conventional usage in this discussion. The trap here of inventing terms is that your term would not account for Ohmic loss as either forward or reverse power in the balance sheet (and this loss could well be the source of mismatch); and yet this loss would have a definite impact on what is "transmitted." A simple instance proves this. Add a 14 Ohm resistor in series at the feed to a perfect quarterwave radiator. The reverse reading would be nada, the forward reading would NOT be "transmitted" power. Further, the conventional usage of terms seen in this thread would still be accurate. 73's Richard Clark, KB7QHC |
#8
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"Jeff" wrote in
.com: The so called "forward power" and "reflected power" are notional values, but not actual power "components". The only power is the average rate at which energy passes a point, and it is in one direction or the other. I am sorry, but I disagree, forward power is real and can be measured, or if you wish separated out with a circulator or isolator. What you are describing could be called 'transmitted' power or power delivered into a mismatched load, but that it different from forward power, or the power delivered by the source. Jeff, You dropped a number of terms he - 'transmitted' power; - power delivered into a mismatched load; - forward power; - power delivered by the source; The power delivered to a load (of any kind) from a lossless transmission line section, is the same as the power delivered by the source. In the case of the lossy line, then the line characteristics and load impedance also need to be taken into account to calculate the power lost in the line section, and it is not as simple as using up a dB/100' rating in a table (unless the line is matched). You assertion that you have travelling forward and reflected power waves on the transmission line runs into a problem when you try to analyse the combination of both at a point (eg the input to the line) as power doesn't combine vectorially. When you devise configurations with circulators, isolaters, directional couplers, hybrids etc to "trap and reroute" reflected power, you have probably changed the nature of the load on a line section and that accounts for why the reflected power seems to have been isolated from forward power. Owen |
#9
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Owen Duffy wrote:
The so called "forward power" and "reflected power" are notional values, but not actual power "components". The only power is the average rate at which energy passes a point, and it is in one direction or the other. That statement depends upon the definition of "power" being used. The IEEE Dictionary has a different definition of power than does a physics textbook. The net power is the average rate at which net energy passes a point. The net power is the difference between the forward joules/sec and the reflected joules/sec. Instead of using the word "power", let's switch over to the dimensions of power, i.e. "joules/second". Those joules are indeed *actual energy components*. The so called "forward power" is a forward traveling EM wave containing energy moving at the speed of light. There are indeed actual forward joules/sec moving past a point on the transmission line. The so called "reflected power" is a rearward traveling EM wave containing energy moving at the speed of light. There are indeed actual reflected joules/sec moving past a point on the transmission line. Note that an EM wave cannot stand still. According to the theory of relativity, EM waves always move at the speed of light (taking VF into account). Standing waves consist of a forward traveling wave containing joules/second and a reflected traveling wave containing joules/second. The joules/second in those two waves are supplied during the transient power-on state. During steady-state, that energy has not yet reached the load. But the total energy contained in the transmission line during steady-state is exactly the amount of energy needed to support the forward traveling wave and the reflected traveling wave. Standing waves would not be possible without those two real EM wave energy components traveling in opposite directions. At power-down, assuming the source is disconnected from the transmission line, all of the forward wave energy and reflected wave energy stored in the lossless transmission line is eventually dissipated in the load. That happens during a time when the source is supplying zero energy. -- 73, Cecil http://www.w5dxp.com |
#10
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"Jeff" wrote in
.com: To get the power delivered to the load, you must subtract reflected power from forward power. In your case that seems to be: Pfwd - Pref = Pload = ~Psource 200w - 100w = 100w = ~100w How can that be? If the meter is basically a directional coupler then the forward power is just that. Subtracting any reflected power will just give a stupid answer. The only errors will be due to the directivity of the coupler, which will give a band of uncertainty which varies with VSWR, and the error due to the accuracy of the detectors. Depends if the meter is before or after the tuner. If the meter is after the tuner, then the tuner is taking reflected power and adding it to the transmitter's contribution. My Bird does not subtract any reflected power to give a forward power reading!! It can't I need to rotate the slug to read reverse power. If you put your bird AFTER a tuner on a line that's near 6-to-1, it will also show twice as much power as the transmitter is putting into the tuner. Or a bit less if the tuner is not efficient. -- Dave Oldridge+ ICQ 1800667 |
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