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On 29 Apr, 04:48, "Mike Lucas" wrote:
"art" wrote: I would say you are close enough to say you are correct. Because you chose a dipole which is in a state of equilibrium and thus particles projected from the dipole cannot collide with other particles from other parasitic radiators. Aren't you not basically refering to the foundations of Poyntings vector which like Gauss is refering to an item in equilibrium when subjected to a time variable of zero value ? If the item is not in a state of equilibrium collision of particles may well occur without a radiation field reaction thus one cannot calculate the resultant field since energy transfer due to particle collision prevents the return of particles to the mother radiator. I've been reading Art's posts for some time now, mostly for the entertainment value. Some of the recent posts were starting to make sense, and this was causing me some concern: that my bafflegab filter in the computor (sic) had gone out. Well, the above quote was a wakeup call... I don't have a clue what he's saying. Can someone translate, please. Mike W5CHR Mike, you must first understand that that two unlike particles in combination from the same radiator creates radiation. Lock that into your mind. Other collisions or combinations do not creat radiation so their energy has to be ascertained so they do not finish up on the radiation side of the equation. If the radiating article is in equilibrium there is no other radiator in competition in the same space to create radiation thus the single radiator is free to emit particles in isolation where errent collisions or combinations can not occur. You must also note that all particles emitted from a single radiator do not all finish up on the radiation side of the equation since some return to the mother element with the same kinetic impact that was imparted on them in the first place and thus these must be accounted for in any equation. If one is to ascertain the final arrangement of any energy transfer from a black box it is desirable not to introduce energy exchange phenomina by introducing rival or cumulative exchanges which cannot be accounted for. All equations that do not allow for the unit of time are purely mathematical exercises of theory thus one must be absolutely sure that the numbers add up on both sides of the equation to justify the addition of that very important symbol called equal. That is why the subject of ther terms of "time" and "equilibrium" is important to transform an equation from a fantasy form to one of reality in both Poyntings vector and the Gaussian equation. Art |
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