John Smith I wrote:
Since the law of conservation of energy exists, I am assuming you
consider some relationship of E/I to have changed in the VHF photon as
opposed to the HF photon--since there is no way for the 5 watts HF to
have different power levels than 5 watts VHF?

Five joules of HF (10 MHz) requires ten times as many
photons as five joules of VHF (100 MHz). What HF photons
lack in energy, they make up for in quantity.

I get ~7.553x10^28 photons in 5 joules of 10 MHz RF
energy and ~7.553x10^27 photons in 5 joules of 100
MHz RF energy.

The E-field/B-field ratio is the same for both in
free space.
--
73, Cecil http://www.w5dxp.com