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VSWR doesn't matter?
Jerry Martes wrote:
"David G. Nagel" wrote in message ... Tim Wescott wrote: billcalley wrote: We are all told that VSWR doesn't matter when using low loss transmission lines, since the RF energy will travel from the transmitter up to the mismatched antenna, where a certain amount of this RF energy will reflect back towards the transmitter; after which the RF will then reflect back up to the antenna -- where the energy is eventually radiated after bouncing back and forth between the transmitter and antenna. I understand the concept, but what I don't quite understand is why the reflected RF energy isn't simply absorbed by the 50 ohm output of the transmitter after the first reflection? For the RF to bounce back and forth, wouldn't the transmitter's impedance have to be very, very high (or low) when the reflected RF energy hit its output stages? I know I'm missing something vital here... That's assuming you use an antenna tuner. The tuner will transform the transmitter's output impedance* just as it transforms the line. Were the transmitter output impedance actually at 50 ohms, on the other side of the tuner it would have the same VSWR as the line when everything was tuned up. Having said that, the VSWR _does_ matter somewhat when using low loss lines, both because the line loss is low but not zero, and the tuner loss will tend to go up as you correct for higher and higher VSWR. * I am _not_ going to start the Big Transmitter Output Impedance Debate. sed denizens -- just don't comment on what a transmitter's "actual" output impedance may be, lest you start a flame war. If you want a quick lesson in high vswr find a ham with an old tube transmitter and see if he will hook it up to a mismatched load. The cherry red plates are the reflected energy being absorbed. Transistors will just turn to smoke under the same conditions. Dave WD9BDZ Hi david Wouldnt it be OK to have a high VSWR along the transmission line if the "tank ckt" can be adjusted to match the load to the transmitter output impedance? That is, the VSWR along the transmission could concievely be high, yet, with proper "tank ckt" adjustment that impedance seen by the output circuit (plate) wouldnt result in a "cherry red plate". What I am asking is ? is the transmission line VSWR directly related to "plate reddening"? I'm more asking than *telling*. Jerry Jerry; The point I was trying to make is that the reflected current is disapated as heat in the finals if the transmitter isn't matched to the load. In a tube radio the tank circuit is the equivilent of an antenna match/tuner and converts the 2000 or so ohms at the plate to the 50 ohms of the transmission line and the unknown ohms of the mis matched antenna. Dave WD9BDZ |
VSWR doesn't matter?
On Mar 12, 4:56 am, Richard Clark wrote:
On 11 Mar 2007 20:39:46 -0700, "Bob" wrote: The active part of the transmitter output isn't 50 ohm. That would cause half the power to be lost as heat in the output stage. Hi Bob, Well, aside from the initial misunderstanding of how power gets to the load (much less back, and then to the load again); I will put to you a question that has NEVER been answered by those who know what the transmitter output Z ISN'T: "What Z is it?" 73's Richard Clark, KB7QHC As Tim Williams alludes, it depends on the transmitter design. It will often be complex rarther than resistive. Since the active device changes impedance during a single cycle of the RF signal it may not even be adequately described by a single value in ohms for a paticular frequency if you wish to analyse the case of forward and reflected power. Consider a class C or class E output stage with an output transistor that is low impedance during most of the positive half of a cycle of signal and mostly somewhere near open circuit for the negative half of the cycle. It seems to me that the effect of reflected power is going to be different depending its phase relative to the forward power. I think this also applys to a lesser extent to a class A PA with a nice hi-Q tank circuit. As usually whan this topic comes up, It don't feel like we have arrived at a usefull and convincing model of what happens, possibly because simple descriptions don't cover everything. Bob |
VSWR doesn't matter?
On 12 Mar 2007 23:00:59 -0700, "Bob" wrote:
As Tim Williams alludes, it depends on the transmitter design. Hi Bob, No quantifiable answer I see. It's not unexpected, everyone who knows what it isn't has never been able to say what it is. It seems like the stock answer you give the cop who asks if you know the speed limit. "No. But I wasn't speeding!" The dependency here started with a conventional Ham transmitter, one so ordinary as to be a commodity. The design is not so exotic as to elude a very simple value - except for those who know it isn't 50 Ohms. 73's Richard Clark, KB7QHC |
VSWR doesn't matter?
"Cecil Moore" wrote in message
... Of course, that was a tongue-in-cheek posting. But if you could design a Thevenin equivalent source with a 0.1 ohm source impedance, wouldn't the efficiency calculate out to be pretty high? Class D rules. (Using MOSFETs, the Thevenin equivalent is quite easy to spot, too!) Tim -- Deep Fryer: A very philosophical monk. Website @ http://webpages.charter.net/dawill/tmoranwms |
VSWR doesn't matter?
"Roy Lewallen" wrote
The problem is that the idea of "reflected energy" turning the plates hot is so easy to understand, that people aren't willing to abandon it simply because it isn't true. _____________ But reflected energy/power does exist. For an easy example, such reflections are evident in the picture seen on an analog TV receiver when the match between the transmit antenna and the transmission connected to it is bad enough. In analog TV transmit systems with a typical 500+ foot length transmission line from the tx to the antenna, a 5% reflection from a far-end mismatch can be quite visible, showing as a "ghost" image that is offset from the main image as related to the round-trip propagation time of the transmission line. RF |
VSWR doesn't matter?
Jimmie D wrote:
"Dan Bloomquist" wrote in message ... billcalley wrote: We are all told that VSWR doesn't matter when using low loss transmission lines, since the RF energy will travel from the transmitter up to the mismatched antenna, where a certain amount of this RF energy will reflect back towards the transmitter; after which the RF will then reflect back up to the antenna -- where the energy is eventually radiated after bouncing back and forth between the transmitter and antenna. As pointed out, VSWR does matter. A lot of bouncing means you heat the transmission line with the power instead of radiating the power. 'Doesn't matter', really means it can be tolerated if need be. I understand the concept, but what I don't quite understand is why the reflected RF energy isn't simply absorbed by the 50 ohm output of the transmitter after the first reflection? For the RF to bounce back and forth, wouldn't the transmitter's impedance have to be very, very high (or low) when the reflected RF energy hit its output stages? I know I'm missing something vital here... Here is what you are missing. In the case of the output, (real/resistive component of the transmitter), seeing the reflected wave, it is _not_ reflecting that power back up the transmission line as you think it is. It would go back to that real impedance and heat the transmitter. Here is what is done with a miss match in the real world. trans-output - match - line - antenna The 'match' is where the magic happens. All the energy coming down the line that got reflected from the antenna 'sees' the 'trans-output - match' as a perfect reflector and gets bounced back[*]. On the other side of the match is the trans-output. There the trans-output sees a perfect impedance, (technically, the conjugate of the trans-output), so that all the power travels through the match toward the antenna. The magic is that when the match is tuned, both of the above conditions are satisfied. *The reflected wave sees a purely reactive reflector not just because of the network but also because of the output power of the transmitter. Without transmitter power the impedance as seen from the load will dramatically change. Best, Dan. Saying that SWR doesnt matter is a rather broad statement(like saying never or always) but I have know of antenna systems having an SWR of 30:1 and his was normal. The feedline was balanced line made of 1 inch copper. Of course an SWR lie this on coax could be fatal to coax and equipment. A more common example of this is the 1/4 wl matching section on a J-pole antenna. It matches 50 ohms to a few Kohms so an SWR of 60: 1 or so would not be unusal here.S oas long as the feedline can handle the current and voltage peaks without much los it doesnt matter much as long as the source impedance is matched to the impedance at the input to the transmission line.Im sure there is a practical limit though. Hi Jimmie, Keep in mind I'm answering in the context of the op's post. And the theoretical SWR on a stub is infinite. The point of the stub at the antenna is to keep the SWR on the transmission line in a reasonable range, to make a match if you will. To put high SWR on the feedline instead of matching at the antenna isn't a great idea in my book. OTOH. I finally did some sidebanding a couple of months ago. (First time on HF.) I got my hands on an old swan 500c. After changing the 6je6's and supply caps, I had to find out what it was like to get on the air. I ran outside and hung a wire between the lab and the shop. 40-50 feet. Put a couple of alligator clips on the end of a chunk of rg-58 and into the window. I started looking for the antenna through the trans-match with an antenna bridge. The tuning was very sharp, lots of Q. I don't know if I could have found it without the bridge :) I was willing to tolerate the miss match to get on the air. Well, it worked out. I made some great QSLs across the mid west and into northern CA. I live in Vernon AZ. I'm pleased this turned out to be as great a radio location as I thought. It shouldn't be long before I get a beam on a tower. By then I'll look to match at the antenna and keep the SWR off the feed line as much as possible. Best, Dan. |
VSWR doesn't matter?
Roy Lewallen wrote:
Yes! All that matters to the transmitter is the impedance it sees. It doesn't know or care that you've mathematically separated the delivered power into "forward" and "reverse" components. It doesn't know or care what the SWR is on the transmission line connected to it, or even if a transmission line is connected at all. Well, without a line, you don't have a real component to tune into. Drawing arcs on a smith chart from an open line with capacitors and coils will only get you to another purely reactive point. Best, Dan. |
VSWR doesn't matter?
In rec.radio.amateur.antenna Roy Lewallen wrote:
David G. Nagel wrote: If you want a quick lesson in high vswr find a ham with an old tube transmitter and see if he will hook it up to a mismatched load. The cherry red plates are the reflected energy being absorbed. Transistors will just turn to smoke under the same conditions. Unfortunately, you'd be learning the wrong lesson. The cherry color is due to the transmitter being loaded with an impedance it's not designed for, causing the final to run at low efficiency. You can disconnect the antenna and replace it with a lumped RC or RL impedance of the same value and get exactly the same result. Alternatively, you can attach any combination of load and transmission line which give the same impedance, resulting in a wide variation of "reflected energy", and get exactly the same result. All that counts is the impedance seen by the transmitter, not the VSWR on the line or the "reflected power". The problem is that the idea of "reflected energy" turning the plates hot is so easy to understand, that people aren't willing to abandon it simply because it isn't true. See http://eznec.com/misc/Food_for_thought.pdf for more. Roy Lewallen, W7EL The fact that any transmission line and antenna combination can be replaced with an RLC lumped load at the transmitter output and the transmitter can't tell the difference is something that a lot of hams seem to have a problem understanding. What I've never understood is why so many hams have a problem with the concept of equivalent circuits only when antennas and transmission lines are involved. -- Jim Pennino Remove .spam.sux to reply. |
VSWR doesn't matter?
"Dan Bloomquist" wrote in message ... Jimmie D wrote: "Dan Bloomquist" wrote in message ... Hi Jimmie, Keep in mind I'm answering in the context of the op's post. And the theoretical SWR on a stub is infinite. The point of the stub at the antenna is to keep the SWR on the transmission line in a reasonable range, to make a match if you will. To put high SWR on the feedline instead of matching at the antenna isn't a great idea in my book. Sure yoiu can, that stub is a transmission line. It would matter if it s a 1/4 wl long or 21 1/4 wl long. If it is designed to handle the current and voltage peaks it can transmit power with low loss when a high VSWR is present. Its just that most people dont make there feedlines out of inch copper tubing. Even with 450 ohm ladder line 10:1 VSWR is very acceptable. |
VSWR doesn't matter?
Richard Fry wrote:
"Roy Lewallen" wrote The problem is that the idea of "reflected energy" turning the plates hot is so easy to understand, that people aren't willing to abandon it simply because it isn't true. _____________ But reflected energy/power does exist. For an easy example, such reflections are evident in the picture seen on an analog TV receiver when the match between the transmit antenna and the transmission connected to it is bad enough. In analog TV transmit systems with a typical 500+ foot length transmission line from the tx to the antenna, a 5% reflection from a far-end mismatch can be quite visible, showing as a "ghost" image that is offset from the main image as related to the round-trip propagation time of the transmission line. RF Richard, You are undoubtedly correct, but you have also demonstrated what is really the lifeblood of many arguments in RRAA. You have introduced both transient behavior and multi-frequency behavior. Clearly these are important in the real world. However, the vast majority of models and calculations used as support for RRAA postings are steady-state and monochromatic. Anyone who stayed awake through calculus and differential equations might recall that the equations for steady-state and transient behavior are often quite different. No one denies the existence of reflections. Some people get confused by the mathematics of power and voltage. But a big argument is about the round-trip travel of energy in the steady-state. Some people seem to believe that energy continues to flow back and forth from one end of a (mismatched) transmission line to the other under steady-state conditions, even simultaneously traveling in both directions. (Passing like ships in the night?) Since energy is a scalar quantity, and any given joule is not distinguishable from another, it is not clear how the proponents keep track of the bookkeeping, but they muddle through somehow. 73, Gene W4SZ |
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