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On Mar 28, 7:38 pm, Cecil Moore wrote:
Keith Dysart wrote: Once again the hypothetical equality Preflected = Pdissipated + Pre-reflected 229.6 = 872 + 0 does not hold. I have pointed out your errors and misconceptions 3-4 times and you have refused to correct them. This is the last time I am going to waste my time. The source is a 2A Norton with a shunt 450 ohm resistor. During steady-state, the source sees 75 ohms. Adding 1WL of 75 ohm lossless line doesn't change anything but for the Nth time, points out your errors and misconceptions. source--1WL 75 ohm line--+--1000' 450 ohm line--75 ohm load Pfor1-- Pfor2-- Pload --Pref1 --Pref2 Taking your numbers, Pload = 220.4w, Pfor2 = 450w, and Pref2 = 229.6w Obviously Pfor1 = Pload = 220.4w and Pref1 = ZERO The joules/sec into the impedance discontinuity must equal the joules/sec out of the impedance discontinuity. Let's see if they do. Pfor1 + Pref2 = Pref1 + Pfor2 220.4 + 229.6 = ZERO + 450 450 joules/sec = 450 joules/sec There you have it. You simply made a mistake. There is NO violation of the conservation of energy principle. The same conditions that exist at the impedance discontinuity also exist at the source. Total destructive interference toward the source is accompanied by total constructive interference toward the load. Every sliver of energy is accounted for. You analysis is, once again, simply wrong. -- 73, Cecil http://www.w5dxp.com I didn't catch this first time round, but better late then never. As you say, adding 1 wavelength of 75 Ohm line will not change the steady state. So the condition on the right side of the inserted 75 Ohm line section will be reproduced on the left side of the line section. This means that reflecting back into the generator from the left end of the 75 Ohm line will be the same Pref2 = 229.6 W that exists on the right side of the 75 Ohm line section. If you doubt, do the same energy analysis for the left end of the line that you did for the right end. The generator is putting 450 W forward into the connection to the 75 Ohm line, 229.6 W is being reflected and 220.4 W is entering the 75 Ohm line. All is in balance at the connection at the left end as it is at the right end. But 229.6 W are going back into the generator. Where do these Watts go? Using your analytical approach it may help if you put a one wavelength section of 450 Ohm line between the generator and the 75 Ohm line section previously inserted. This will not change the steady state result but may make it easier to visualize the reflected 229.6 W. ....Keith |
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