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#1
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Art wrote:
"I have his (Kraus`) second edition (Antennas) and I find no mention of radiation from the beginning where current is applied onward." I think I have that edition too. If you review the chapter on "Point Sources" you`ll find: power patterns, a power theorem and its application to isotropic sources, rediation intensity, source with hemispheric power pattern, unidirectional cosine power pattern, etc., etc.. The new, now available 3rd ed. of "Antennas" by Kraus, Marhefka, and a host of others is greatly expanded and improved. It is worth the investment. Being uncertain of what Art really wants, doesn`t stop me from advising him to start by having a look at the famous Sommerfeld formula on page 804 of Terman`s 1955 opus. It predicts 1 kilowatt will produce 186 mv per m at a distance of 1 mile from a short vertical transmitting antenna given a certain ground conductivity and other conditions. Best regards, Richard Harrison, KB5WZI |
#2
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#3
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Richard Clark, W7QHC wrote:
"-you know, the basic stuff of propagation." I may be able to respond to a question, but I don`t write books. On the question of ground conductivity and polarization: Soil loss makes vertically polarized waves tilt forward in the direction of their travel as if dragging their feet. It`s not all bad as this tilt makes a horizontal antenna, the Beverage, receive these vertically polarized waves well. Best regards, Richard Harrison, KB5WZI |
#4
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On 27 Mar, 15:12, (Richard Harrison) wrote:
Art wrote: "I have his (Kraus`) second edition (Antennas) and I find no mention of radiation from the beginning where current is applied onward." I think I have that edition too. If you review the chapter on "Point Sources" you`ll find: power patterns, a power theorem and its application to isotropic sources, rediation intensity, source with hemispheric power pattern, unidirectional cosine power pattern, etc., etc.. The new, now available 3rd ed. of "Antennas" by Kraus, Marhefka, and a host of others is greatly expanded and improved. It is worth the investment. Being uncertain of what Art really wants, doesn`t stop me from advising him to start by having a look at the famous Sommerfeld formula on page 804 of Terman`s 1955 opus. It predicts 1 kilowatt will produce 186 mv per m at a distance of 1 mile from a short vertical transmitting antenna given a certain ground conductivity and other conditions. Best regards, Richard Harrison, KB5WZI Richard, I have lots of books but as yet have not found the answer even tho many have posted none appear to really have an answer other than to throw stones. You apparently have found the answer! Could you quote from the books that you are refering to the angle of radiation relative to the radiator, thats it ? If you can't understand that then relay to me the angle of a radiation front relative to a radiator, I'm sure some other people are interested in what you found. Even better, let me know the TOA of a dipole in free space and how much it varies to that of the same dipole over a perfect ground. Use a computor program if you like, anything that sheds light on the matter . The books say that a horizontal "v" antenna should be tipped for max gain, doesn't that raise your interest about the reasoning and mathematics behind this? Jimmie D asked me to state this angle but I have only a expensive computor program that doesn't give the math with the answer. Please read off the angle and the specifics so we all can move on, I don't want a 160 thread postings some thrust upon Walt Art |
#5
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Art wrote:
"Could you quote from the books that you are referring to the angle relative to the radiator, that`s it?" O.K.. but the angle is relative to the horizontal in the statement. Termans 1955 opus on page 804 says the strength of radiation from a short vertical antenna is proportional to the cosine of the elevation angle. That`s right because at zero angle, radiation is maximumm as cosine of zero degrees is 1, and cosine of 90 degrees is zero. Best regards, Richard Harrison, KB5WZI |
#6
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On 27 Mar 2007 16:39:52 -0700, "art" wrote:
On 27 Mar, 15:12, (Richard Harrison) wrote: Art wrote: "I have his (Kraus`) second edition (Antennas) and I find no mention of radiation from the beginning where current is applied onward." I think I have that edition too. If you review the chapter on "Point Sources" you`ll find: power patterns, a power theorem and its application to isotropic sources, rediation intensity, source with hemispheric power pattern, unidirectional cosine power pattern, etc., etc.. The new, now available 3rd ed. of "Antennas" by Kraus, Marhefka, and a host of others is greatly expanded and improved. It is worth the investment. Being uncertain of what Art really wants, doesn`t stop me from advising him to start by having a look at the famous Sommerfeld formula on page 804 of Terman`s 1955 opus. It predicts 1 kilowatt will produce 186 mv per m at a distance of 1 mile from a short vertical transmitting antenna given a certain ground conductivity and other conditions. Best regards, Richard Harrison, KB5WZI Richard, I have lots of books but as yet have not found the answer even tho many have posted none appear to really have an answer other than to throw stones. You apparently have found the answer! Could you quote from the books that you are refering to the angle of radiation relative to the radiator, thats it ? If you can't understand that then relay to me the angle of a radiation front relative to a radiator, I'm sure some other people are interested in what you found. Even better, let me know the TOA of a dipole in free space and how much it varies to that of the same dipole over a perfect ground. Use a computor program if you like, anything that sheds light on the matter . The books say that a horizontal "v" antenna should be tipped for max gain, doesn't that raise your interest about the reasoning and mathematics behind this? Jimmie D asked me to state this angle but I have only a expensive computor program that doesn't give the math with the answer. Please read off the angle and the specifics so we all can move on, I don't want a 160 thread postings some thrust upon Walt Art The take-off angle of a dipole in free space? The angle with respect to what? Walt, W2DU |
#7
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On 31 Mar, 14:36, Walter Maxwell wrote:
On 27 Mar 2007 16:39:52 -0700, "art" wrote: On 27 Mar, 15:12, (Richard Harrison) wrote: Art wrote: "I have his (Kraus`) second edition (Antennas) and I find no mention of radiation from the beginning where current is applied onward." I think I have that edition too. If you review the chapter on "Point Sources" you`ll find: power patterns, a power theorem and its application to isotropic sources, rediation intensity, source with hemispheric power pattern, unidirectional cosine power pattern, etc., etc.. The new, now available 3rd ed. of "Antennas" by Kraus, Marhefka, and a host of others is greatly expanded and improved. It is worth the investment. Being uncertain of what Art really wants, doesn`t stop me from advising him to start by having a look at the famous Sommerfeld formula on page 804 of Terman`s 1955 opus. It predicts 1 kilowatt will produce 186 mv per m at a distance of 1 mile from a short vertical transmitting antenna given a certain ground conductivity and other conditions. Best regards, Richard Harrison, KB5WZI Richard, I have lots of books but as yet have not found the answer even tho many have posted none appear to really have an answer other than to throw stones. You apparently have found the answer! Could you quote from the books that you are refering to the angle of radiation relative to the radiator, thats it ? If you can't understand that then relay to me the angle of a radiation front relative to a radiator, I'm sure some other people are interested in what you found. Even better, let me know the TOA of a dipole in free space and how much it varies to that of the same dipole over a perfect ground. Use a computor program if you like, anything that sheds light on the matter . The books say that a horizontal "v" antenna should be tipped for max gain, doesn't that raise your interest about the reasoning and mathematics behind this? Jimmie D asked me to state this angle but I have only a expensive computor program that doesn't give the math with the answer. Please read off the angle and the specifics so we all can move on, I don't want a 160 thread postings some thrust upon Walt Art The take-off angle of a dipole in free space? The angle with respect to what? Walt, W2DU- Hide quoted text - - Show quoted text - Always zero Walt since it takes two dipoles to tango. |
#8
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Art wrote:
"Even better, let me know the TOA of a dipole in free space and how much it varies to that of the same dipole over perfect ground." If possible, look at Terman`s1955 opus page 882: "Effect of Ground on the Directional Pattern of Ungrounded Antennas - Image Antennas." In free space, no reflecting surface is nearby to distort the pattern of a radiator. Terman gives the familiar radiation of a 1/2-wave dipole in space in Fig. 23-4(a) on page 867. Terman says on page 883: "For purposes of calculation, it is convenient to consider that the reflected wave is generated, not by reflection, but rather by an "image" antenna located below the surface of the ground." The summation of the direct and reflected waves from a horoizontal wire above the earth often has serious consequences as Terman notes on page 885: "Consequently, to obtain strong radiation in directions approaching the horizontal using a horizontally polarized radiating system, it is necessary that the height of the antenna above the earth be in the order of one wavelength or more." Terman shows the vertical radiation patterns for a horizontal wire at various heights above the earth in Fig. 23-21 on page 884. Note that half-wave elevation concentrates most energy into a good elevation angle for sky wave reflection at some frequencies and distances. Best regards, Richard Harrison, KB5WZI |
#9
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Richard Harrison wrote:
[snip] Terman says on page 883: "For purposes of calculation, it is convenient to consider Richard, Great quote! If people listened to the words of the master, there would be far fewer arguments on RRAA. 73, Gene W4SZ |
#10
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Art wrote:
"Even better, let me know the TOA of a dipole in free space and how much it varies to that of the same dipole over perfect ground." If possible, look at Terman`s1955 opus page 882: "Effect of Ground on the Directional Pattern of Ungrounded Antennas - Image Antennas." In free space, no reflecting surface is nearby to distort the pattern of a radiator. Terman gives the familiar radiation of a 1/2-wave dipole in space in Fig. 23-4(a) on page 867. Terman says on page 883: "For purposes of calculation, it is convenient to consider that the reflected wave is generated, not by reflection, but rather by an "image" antenna located below the surface of the ground." The summation of the direct and reflected waves from a horoizontal wire above the earth often has serious consequences as Terman notes on page 885: "Consequently, to obtain strong radiation in directions approaching the horizontal using a horizontally polarized radiating system, it is necessary that the height of the antenna above the earth be in the order of one wavelength or more." Terman shows the vertical radiation patterns for a horizontal wire at various heights above the earth in Fig. 23-21 on page 884. Note that half-wave elevation concentrates most energy into a good elevation angle for sky wave reflection at some frequencies and distances. Best regards, Richard Harrison, KB5WZI |
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